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Leya [2.2K]
3 years ago
8

Which ordered pair is a solution to the system of equations?

Mathematics
2 answers:
Kazeer [188]3 years ago
7 0

Answer:

B) (-2,1)

Step-by-step explanation:

In order to find a solution to a system of equations, substitute the point's x and y values into both of the equations, solve, and see if it makes the equation true.

1) Let's try the point (-2,1). First, substitute its x and y values into the first equation, 3x - 3y = -9. Thus, substitute -2 for x and 1 for y in the equation and solve:

3x-3y = -9\\3(-2)-3(1) = -9\\-6 - 3 = -9 \\- 9 = -9

-9 does equal -9, thus (-2, 1) makes the first equation true.

2) Now, do the same thing but with the second equation, 2x + y = -3. Again, substitute -2 for x and 1 for y and solve:

2x + y = -3\\2(-2) + (1) = -3\\-4 + 1 = -3\\-3 = -3

-3 does equal -3, thus (-2, 1) makes the second equation true.

By substituting its values into both equations, we saw that it made both equations true. Thus, (-2,1) is the answer.

elixir [45]3 years ago
4 0
I believe it would be (b) (-2,1)
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Answer:

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Step-by-step explanation:

<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>

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<u>Now we can evaluate the terms in the brackets. </u>

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3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)

<u>We can open the brackets now. One plus and one minus makes a minus. </u>

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18

<u>Evaluate like terms.</u>

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3a^{4} + 11a³ - 7a² + 18a - 18

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