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3 years ago

PLEASE HELP!!! write a 10 line free verse poem about cosmetology

Mathematics

2 answers:

Lemur [1.5K]3 years ago

7 0

Step-by-step explanation:

Free verse is the name given to poetry that doesn't use any strict meter or rhyme scheme. ...
William Carlos Williams's short poem “
The Red Wheelbarrow” is written in
free verse. It reads: “so mu
ch dep
ends / upon / a red wheel / barrow / glazed with rain / water / beside .
the white / ch
ickens.”

dalvyx [7]3 years ago

3 0

Answer:

First, settle on a theme or event you'd like to write about. Try to set the scene in your head and go from there. Then write down some key words that relate to your story. Since you don't need to worry about matching up words and rhyming them, you should be able to incorporate most of these words in your poem

Step-by-step explanation:

Poem is,

When I sitting heard the astronomer where he lectured with much applause in the lecture-room,

How soon unaccountable I

became tired and sick,

Till rising and gliding out I

wander’d off by myself,

In the mystical moist night-air,

and from time to time,

Look’d up in perfect silence at the

stars.

You might be interested in

In a triangle ABC, AB = 7, AC = 8, BC = 3, what is cos(A)?

kotegsom [21]

Use the cosine rule.
c=AB=7
b=AC=8
a=BC=3
a^2=b^2+c^2-2bc(cos(A))
=>
cos(A)=(b^2+c^2-a^2)/(2bc)
=(7^2+8^2-3^2)/(2*7*8)
=13/14
=0.9286

6 0

3 years ago

Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3

Serhud [2]

Answer:

$e^{3t}(2t+5t^{2})$

Step-by-step explanation:

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=$

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem: $L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)$

$L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]$

Separate the fraction in a sum:

$e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])$

The formula for this is:

$L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}$

Modify the expression to match the formula.

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])$

Solve

$e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )$

6 0

3 years ago

A science class has a ratio of 3 boys and 2 girls. Can there be 24 students in the class?

guajiro [1.7K]

Answer:

Let 3x be the number of boys

Let 2x be the number of girls

3x + 2x = 24

5x = 24

x = 4.8

3(4.8) = 14.4 boys

2(4.8) = 9.6 girls

There can't be 24 students for a ratio of 3 boys and 2 girls, because there can't be 14.4 boys and 9.6 girls, it has to be an exact number, otherwise it wouldn't make any sense.

For example, you and I are both 1 person, we can't be half a person or 0.6 of a person, only 1.

3 0

3 years ago

Read 2 more answers

3. Problema 2: Suponga que un fabricante de radios tiene la función de costo total C (x) = 43x + 1850 dólares y la función de in

allochka39001 [22]

Responder:

$ 11,137

Explicación paso a paso:

Como no se nos dice qué encontrar, también podemos encontrar el beneficio obtenido por la venta de 351 unidades de radio.

Dado

Función de costo C (x) = 43x + 1850

Función de ingresos R (x) = 80x

Obtener la función de ganancias

P (x) = R (x) - C (x)

P (x) = 80x - (43x + 1850)

P (x) = 80x - 43x - 1850

P (x) = 37x - 1850

Si se fabrican 351 radios, la ganancia obtenida se calculará como se muestra a continuación:

P (351) = 37 (351) - 1850

P (351) = 12,987-1850

P (351) = 11,137

Por lo tanto, la ganancia obtenida de las ventas de 351 radios es de $ 11,137

5 0

3 years ago

The mean of the data set(9,5,y,2,x)is twice the data set (8,x, 4,1,3).What is (y-x)

pantera1 [17]

Answer:

y - x = 16

Step-by-step explanation:

Explanation:-

Step(i):-

Given data set A is 9,5,y,2,x

Mean of the Data set A

= $\frac{9 + 5 + y + 2 +x}{5}$

= $\frac{16 +x+y}{5}$

Given data set B is 8, x, 4, 1, 3

Mean of the Data set B

= $\frac{8+ x+4+1+3}{5}$

Step(ii):-

Mean of the Data set A = 2 X Mean of the Data set B

$\frac{16 +x+y}{5} = 2 X \frac{16+x}{5}$

On simplification , we get

16 +x + y = 2( 16 +x)

16 + x + y = 32 + 2 x

16 + x + y - 32 - 2 x = 0

y - x -16 =0

y - x = 16

5 0

3 years ago