All categories

2 years ago

Please help me with this problem i have been struggling!

Mathematics

2 answers:

adoni [48]2 years ago

5 0

Answer:

First multiply

1 and 3/4 by 8 and then you got your answer

Rom4ik [11]2 years ago

5 0

14 cups is the answer

You might be interested in

4. Joe received an hourly wage of $8.15. His boss gave him a 7% raise. How much does Joe make per hour now?

Olenka [21]

Answer:

$ 8.72

Step-by-step explanation:

How much does Joe make per hour now?

$8.15 + 7%·$8.15 =

= $8.15 + 7×8.15/100

= $8.15 + $57.05/100

= $8.15 + $0.57

= $ 8.72

5 0

3 years ago

Read 2 more answers

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed

Olegator [25]

Answer:

The length of shadow decrease at 0.48 m/s.

Step-by-step explanation:

The distance of man from building = x

Thus initially, x = 12

It is given that dx/dt= -1.3 m/s

Let the shadow height = Y

Now solve for the $dy/dt$ when x=4

from the diagram (triangle) it can be seen similar triangles with similar base/height ratios.

$\frac{2}{12-x} = \frac{y}{12} \\Y = \frac{24}{12 - x} \\ \frac{dy}{dt} = \frac{24}{(12-x)^{2}} \times \frac{dx}{dt} \\at x=4, dy/dt \ becomes: \\\frac{24}{(12-4)^2} \times -1.3 \\= -0.48 m/s$

8 0

3 years ago

A restaurant bill is $25.80. How<br> much is a 20% tip for this bill (NOT<br> the total)?

lozanna [386]

Answer:

25 pesos 80 pw

pesos I'm not sure

Step-by-step explanation:

25. 80

3 0

2 years ago

These are the means and standard deviations for samples of prices from two

marysya [2.9K]

Its Letter B!!!!!!!!!!!!

7 0

2 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

3 years ago