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3 years ago

Please help me with this problem i have been struggling!

Mathematics

2 answers:

adoni [48]3 years ago

5 0

Answer:

First multiply

1 and 3/4 by 8 and then you got your answer

Rom4ik [11]3 years ago

5 0

14 cups is the answer

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What is the answer to 2(x-5)^2+26=124

Elina [12.6K]

If ur solving for x, the answers are 12 and -2

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3 years ago

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What is the slope of the line through (2,-8) and (4,1)

vekshin1

9/2. turn each coordinate pair into y/x and subtract them. hope this helps :)

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3 years ago

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ANSWER PLEASE A rectangle's length and width are in a ratio of 9:1. The perimeter is 100 inches. What are the length and width?

iren [92.7K]

The length of rectangle is 45 inches and width is 5 inches.

Step-by-step explanation:

Given,

Perimeter = 100 inches

The ratio of length and width = 9:1

It means that 9 times of any number and 1 times of any number will be the original length, therefore,

Let,

x be the that number.

Length = 9x

Width = 1x

Perimeter = 2(Length+width)

$100=2(9x+x)\\100=2(10x)\\100=20x\\20x=100$

Dividing both sides by 20

$\frac{20x}{20}=\frac{100}{20}\\x=5$

Length = 9x = 9*5 = 45 inches

Width = x = 5 inches

The length of rectangle is 45 inches and width is 5 inches.

Keywords: rectangle, perimeter

Learn more about perimeters at:

#LearnwithBrainly

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4 years ago

V=4/3? r^2 Suppose that, for the sphere in the video, instead of being told how fast the radius is changing, we're told that the

grigory [225]

Answer:

$\frac{dr}{dt}=0.01$ cm per second

$\frac{dS}{dt}=320 square centimeter per secondStep-by-step explanation:We are given that volume of sphere [tex]V=\frac{4}{3}\pi r^3$

Volume of sphere is increasing at a constant rate

$\frac{dV}{dt}=4$ cubic centimeters per second

We have to find the rate of radius at which increasing

when r= 10 cm

Differentiating w.r.t time

$\frac{dV}{dt}=\frac{4}{3}\pi\cdot3r^2\frac{dr}{dt}$

$4=4 r^2\frac{dr}{dt}$

$\frac{dr}{dt}= \frac{1}{r^2}=\frac}{1}{(10)^2}=0.01$ cm per second

Now ,we are given that surface area of sphere

$S=4\pir^2$

Differentiate w.r.t time then we get

$\frac{dS}[dt}=8\pir\frac{dr}{dt}$

$\frac{dS}{dt}=8\pi\times 20\times 2$

$\frac{dS}{dt}=320$ cm per second

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3 years ago

Which relation is a function?

prohojiy [21]

The relation that is a function is:

b. y = 2x² - 3x + 7

<h3>When a relation is a function?</h3>

A relation is a function if each value of the input is mapped to only one value of the output.

Hence, when both x and y are squared, we have that $x = \pm ay$ , hence it is not a function. This is the case for items a and c.

For item d, we have that the relation can be simplified as follows:

x = -y² + 3y

x = y(-y + 3)

The solution above, is associated to two values of y, hence it is also not a function. Then the function is given by:

b. y = 2x² - 3x + 7

In the solution, it can be seen that for each input x, only one value of y can be generated.

More can be learned about relations and functions at brainly.com/question/12463448

#SPJ1

3 0

2 years ago