$\bf p(x)=x^4-256\qquad \boxed{2^8=256}\qquad p(x)=x^{2\cdot 2}-2^{4\cdot 2}
\\\\\\
p(x)=(x^2)^2-(2^4)^2\implies p(x)=[x^2-2^4]~[x^2+2^4]
\\\\\\
p(x)=[x^2-(2^2)^2]~[x^2+2^4]\implies p(x)=[(x-2^2)(x+2^2)]~[x^2+2^4]
\\\\\\
p(x)=(x-4)(x+4)(x^2+16)$

8 0

3 years ago

Katherine has 4 red pens, 6 blue pens, and 11 black pens in her book bag. If she randomly pulls out one pen, what is the probabi

sashaice [31]

Answer: 52.38%

Step-by-step explanation:

11 out of 21

11/21

.5238

52.38%

6 0

3 years ago

Got stuck can someone help me

fiasKO [112]

50 dollars per month. It says "after x months" -50x is the variable thats changes.

4 0

4 years ago

5 - (-9 ) subtracting intergers

ruslelena [56]

Answer:

Step-by-step explanation:

Hope this will help you....

4 0

3 years ago

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