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olganol [36]
2 years ago
5

A runner finished a total of 1500 kilometers in races before retiring she finished thirty-two 15 kilometer races. The rest of he

r races were10-kilometer races. How many of her races were 10 kilometer races?
( this is my sister question she doesn't have brainly :) )
Mathematics
2 answers:
Triss [41]2 years ago
8 0

Answer:

102 of runner's races were 10-kilometer races.

Ahat [919]2 years ago
3 0

Answer: 1020

Step-by-step explanation:

In a 5000 m race, the athletes run 12(1)/(2) laps; each lap is 400m . Kara runs the race at a constant pace and finishes in 17.5 min. Hannah runs the race in a blistering 15.3min,  so fast that she actually passes Kara during the race. How many laps has Hannah run when she passes Kara?

Hope This Helps!

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In a triangle RSTV, RS=5.3cm and ST=4.1 find perimeter of RSTV
Luba_88 [7]
Is that a with 4 vertices  ,,,check your question

7 0
3 years ago
Renee uses 12 marshmallows and 8 graham crackers to make 4 s'mores. Drag marshmallows and graham crackers into the box to show h
Anit [1.1K]
To find out how much is needed for 1 you will need to divide each given value by 4:
12 marshmallows / 4 = 3
8 graham crackers / 4 = 2
4 smores / 4 = 1
you then need to multiply each value by 3 :
3 marshmallows x 3 = 9
2 graham crackers x 3 = 6
1 smore x 3 = 3
therefore the answer would be :
9 marshmallows
6 graham crackers

hope this helps you


7 0
3 years ago
Read 2 more answers
Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random
Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

<em>Let </em>\bar X<em> = sample mean</em>

The z-score probability distribution for sample mean is given by;

               Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = $50,000

            \sigma = population standard deviation = $25,000

            n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P(\bar X > $52,000)

  P(\bar X > $52,000) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } } ) = P(Z > 2.53) = 1 - P(Z \leq 2.53)

                                                                    = 1 - 0.9943 = 0.0057

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.</em>

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0
3 years ago
Solve the following: 1) The original cost of an umbrella was $28 but is now on sale for $21. Find the percent of the discount.​
frutty [35]

Answer:

7%

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the percent of decrease if 110 is decreased to 88 A) 125% B)80% C)20%
stich3 [128]

Hey there! I'm happy to help!

We have 110 minus a certain percent of 110 equals 88. Let's call this percent p and solve.

110-110p=88

We subtract 110 from both sides.

-110p=-22

We divide both sides by 110.

p=0.2

Therefore, the percent decrease is C) 20%.

Have a wonderful day! :D

4 0
3 years ago
Read 2 more answers
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