2sinxcosx - sin(2x)cos(2x) = 0
<span>Part I </span>
<span>The double angle identity for sine states that sin(2x) = 2sinxcosx </span>
<span>Thus we get: </span>
<span>sin(2x) - sin(2x)cos(2x) = 0 </span>
<span>Part II </span>
<span>sin(2x)(1 - cos(2x)) = 0 </span>
<span>Part III </span>
<span>Either sin(2x) = 0 or </span>
<span>1 - cos(2x) = 0 </span>
<span>=> cos(2x) = 1 </span>
<span>For sin(2x) = 0, this is true for </span>
<span>2x = n(pi) where n = 0, 1, 2, .... </span>
<span>x = n(pi/2) </span>
<span>For cos(2x) = 1, this is true for </span>
<span>2x = n(pi) where n = 0, 2, 4, .... </span>
<span>x = n(pi/2)
</span>
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Step-by-step explanation:
4x + 12° = 64° ( vertically opposite angle )
4x = 64° - 12°
4x = 52°
x = 52° / 4
x = 13°
hence the value of x is 13°
Answer:
The answer is 30 over 5, 30/5
Answer:
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Step-by-step explanation:
