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Sedaia [141]
3 years ago
13

Ben can paint 280 square feet in 12 minutes. How many square feet can he paint in 1 hour?

Mathematics
1 answer:
NemiM [27]3 years ago
7 0

Answer:

1400 sq. ft

Step-by-step explanation:

60 min = 1 hour

280 sq. ft / 12 min = x / 60 min

x = 60 min * (280 sq. ft / 12 min)

minuets cancel out

x = 1400 sq. ft

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Please help me. After charging for 1/3 of an hour, a phone is at 2/5 of its full power. How long will it take the phone to charg
yanalaym [24]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What
Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}

a) What is the probability that none of the questions are essay?

P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174

b)  What is the probability that at least one is essay?

P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232

c) What is the probability that two or more are essay?

P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594

8 0
3 years ago
Out of -1.81 , 1 3/4 , -1.3 , -1 4/5 is the least or greatest
Juli2301 [7.4K]

Answer:

-1.81 is the least and 1 3/4 is the greatest

Step-by-step explanation:

1 3/4 is also 1.75     -1 4/5 is also -1.8

Ordered from least to greatest:

-1.81, - 1 4/5, -1.3, 1 3/4

5 0
3 years ago
Find each percent of change. Round to the nearest whole percent if necessary. State whether the percent of change is an increase
Sati [7]

Answer:

Percent of Change: 30% (rounded) It is an increase

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
When testing gas pumps for accuracy, fuel-quality enforcement specialists tested pumps andfound that 1304 of them were not pumpi
elena-14-01-66 [18.8K]

Answer:

The p-value of the test statistic from the standard normal table is 0.0017 which is less than the level of significance therefore, the null hypothesis would be rejected and it can be concluded that there is sufficient evidence to support the claim that less than 20% of the pumps are inaccurate.

Step-by-step explanation:

Here, 1304 gas pumps were not pumping accurately and 5689 pumps were accurate.

x = 1304, n = 1304 + 5689 = 6993

The level of significance = 0.01

The sample proportion of pump which is not pumping accurately can be calculated as,

The claim is that the industry representative less than 20% of the pumps are inaccurate.

The hypothesis can be constructed as:

H0: p = 0.20

H1: p < 0.20

The one-sample proportion Z test will be used.

The test statistic value can be obtained as:

Z=\frac{\hat{p}-P}{\sqrt{\frac{P(1-P))}{n}}}\\\\Z=\frac{0.186-0.20}{6993}\\\\Z=-2.927

5 0
3 years ago
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