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3 years ago

Hi- So this is a simple question that I keep forgetting how to answer! HELPPPP

Mathematics

1 answer:

WARRIOR [948]3 years ago

7 0

Answer:

4 times bigger

Step-by-step explanation:

1. The area of an object dilated by a scale factor (SF) will be equal to (SF)^2.

2. For example, let's say the base and height of Triangle A is 4 and 8. The area would be 16 units squared. The base and height of Triangle B would be 8 and 16. The area would be 64 units squared.

3. As you can see from the aforementioned example, the SF (2) was squared and then multiplied by 16 to get 64.

Therefore, Triangle B's area is 4 times bigger than Triangle A's area.

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Whats 337,060 in expanded form

V125BC [204]

300,000 + 30,000 + 7,000 + 6 = 337,060 =)

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4 years ago

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Write an equation in point slope form for the line that passes through one of the following pairs of points. You may choose the

wolverine [178]

(5,1)(-3,4)
slope = (4 - 1) / (-3 - 5) = -3/8

y - y1 = m(x - x1)
slope(m) = -3/8
(5,1)...x1 = 5 and y1 = 1
now we sub
y - 1 = -3/8(x - 5) <=== point slope form

y - 1 = -3/8(x - 5)
y - 1 = -3/8x + 15/8
y = -3/8x + 15/8 + 1
y = -3/8x + 15/8 + 8/8
y = -3/8x + 23/8 <=== slope intercept form

y = -3/8x + 23/8
3/8x + y = 23/8 ...multiply everything by 8
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4 years ago

The probability of having a winning raffle ticket is 15%. If you bought 40 tickets, how many winning tickets should you expect t

lina2011 [118]

You would have a 26% chance. If you cross multiply using 15/100 and 40/x. 100 times 40 then divide by 15.

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3 years ago

Three friends went to a book shop the first bought three bros and four pencils for $30.00. The second bought two Bros and five p

skad [1K]

Answer:

total 66$

Step-by-step explanation:

let price of bro s be x and pencil be y

according to Qn

at 1 cond

3x+4=30____(1)

2x+5y=27____(2)

solve botth and get value of each bros and pencil and then at last add,30$,27$,6$,3$

7 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

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3 years ago