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meriva
3 years ago
9

Help plz! I don't know how to find the domain! Find the domain.

Mathematics
2 answers:
Sever21 [200]3 years ago
8 0
The answer will be 3
abruzzese [7]3 years ago
7 0

Step-by-step explanation:

using interval notation

domain(-infinity, 5) U (5,infinity)

the domain is from negative infinity to 5 but not including 5 and from 5 to infinity but not including 5

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4x – 1 = 7x – 16<br><br> Solve the problem <br> (Show your work)
Katarina [22]

Answer:

x = 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

4x - 1 = 7x - 16

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 4x on both sides:                    -1 = 3x - 16
  2. Add 16 to both sides:                             15 = 3x
  3. Divide 3 on both sides:                          5 = x
  4. Rewrite:                                                   x = 5

<u>Step 3: Check</u>

<em>Plug in x into the original equation to verify it's a solution.</em>

  1. Substitute in <em>x</em>:                    4(5) - 1 = 7(5) - 16
  2. Multiply:                               20 - 1 = 35 - 16
  3. Subtract:                              19 = 19

Here we see that 19 does indeed equal 19.

∴ x = 5 is a solution to the equation.

6 0
3 years ago
Read 2 more answers
What is the general form of the equation of a circle with its center at (3,5)
goldenfox [79]

Answer:

2,5 maybe

Step-by-step explanation:

5 0
3 years ago
Divide. Write your answer using the smallest numbers possible.
Ilya [14]

Answer:

30660

Step-by-step explanation:

8 0
3 years ago
-1/2(-5/6+1/3)<br> Simplify
ivann1987 [24]
Simplified the answer is 1/4 or 0.25 in decimal form
8 0
3 years ago
The director of admissions at the University of Maryland, University College is concerned about the high cost of textbooks for t
nadezda [96]

Answer:

a. There is evidence that the population mean is above $300.

b. There is no evidence that the population mean is above $300.

c. There is no evidence that the population mean is above $300.

d. The director could ask for cheaper similar books.

Step-by-step explanation:

Let X be the random variable that represents the cost of textbooks. We have observed n = 25 values, \bar{x} = 315.4 and s = 43.20. We suppose that X is normally distributed.

We have the following null and alternative hypothesis

H_{0}: \mu = 300 vs H_{1}: \mu > 300 (upper-tail alternative)

We will use the test statistic

T = \frac{\bar{X}-300}{S/\sqrt{25}} and the observed value is

t_{0} = \frac{315.4 - 300}{43.20/\sqrt{25}} = 1.7824.

If H_{0} is true, then T has a t distribution with n-1 = 24 degrees of freedom.

a. The rejection region is given by RR = {t | t > t_{0.9}} where t_{0.9} = 1.3178 is the 90th quantile of the t distribution with 24 df, so, RR = {t | t > 1.3178}. Because the observed value satisty 1.7824 > 1.3178, there is evidence that the population mean is above $300.

b. If s = 75, then the observed value is t_{0} = \frac{315.4 - 300}{75/\sqrt{25}} = 1.0267. The rejection region for a 0.05 level of significance is RR = {t | t > t_{0.95}} where t_{0.95} = 1.7108 is the 95th quantile of the t distribution with 24 df, so, RR = {t | t > 1.7108}. Because the observed value does not fall inside the rejection region, there is no evidence that the population mean is above $300.

c. If \bar{x} = 305.11 and s = 43.20, the observed value is t_{0} = \frac{305.11 - 300}{43.20/\sqrt{25}} =  0.5914. For RR = {t | t > 1.3178} we have that the observed value does not fall inside RR, therefore, there is no evidence that the population mean is above $300.

d. Because the director of admissions is concerned about the high cost of textbooks, and there is evidence that the population mean of costs is above $300, the director could ask for cheaper similar books.

8 0
3 years ago
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