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MAXImum [283]
3 years ago
10

What is the length of BC? A.7 B.12 C.13 D.17 E V60 F. V119

Mathematics
1 answer:
Karolina [17]3 years ago
7 0

Answer:

c. 13

Step-by-step explanation:

c²=a²+b²

c²=5²+12²

c²=169

c=13

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Read 2 more answers
A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.
Tanzania [10]

The total area of pyramid is 113.569 square units

The equation to find the total area of the pyramid is Total area = base area + lateral area.

<u>Solution:</u>

Given, A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.

<em><u>The total area of pyramid is given by:</u></em>

A=A_{b}+A_{l}   ---- eqn 1

Where,

A_{b} \text { is the base area and } A_{l} \text { is the lateral area }

<em><u>The area of base is given as:</u></em>

A_{b}=\frac{3 \sqrt{3}}{2} l^{2}

Where "l" is the side of hexagon.

Substituting we get,

\begin{array}{l}{A_{b}=\frac{3 \sqrt{3}}{2}(4)^{2}} \\\\ {=\frac{3 \sqrt{3}}{2} \times 16=3 \sqrt{3} \times 8} \\\\ {A_{b}=24 \sqrt{3}}\end{array}

<em><u>The lateral area is given as:</u></em>

A_{l}=3 b h

Where,

b: base of the triangle

h: height of the triangle

Substituting we get,

\begin{array}{l}{A_{l}=3 \times(4) \times(6)} \\\\ {A_{l}=72}\end{array}

Plugging in the values we found in eqn 1 we get,

A=24 \sqrt{3}+72

A = 113.569 square units

<em><u>Summarizing the results:</u></em>

The total area of pyramid is 113.569 square units approximately

The equation used to find total area of pyramid is Total area = base area + lateral area.

8 0
3 years ago
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