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liq [111]
3 years ago
14

I need help with a-d

Mathematics
1 answer:
Fed [463]3 years ago
7 0
A. 1.33
B. 133%
C. 13/1000
D. 0.0133
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Which of the following represents the general term for the sequence 1, 3, 5, 7, 9, . . .? n
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Answer:

Step-by-step explanation:

In the given sequence, the terms are increasing in arithmetic progression. The common difference, d between successive terms is 2

The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = 1

d = 2

Therefore, the expression for the general term for the sequence is

Tn = 1 + 2(n - 1)

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3 years ago
Which table of ordered pairs represents a proportional relationship?
grin007 [14]

Answer:

It is the second one

Step-by-step explanation:

A proportional relationship happens when you get the same answer every time that you divide the y by the x.

(2,10) (4,20) (6,30)

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That is not true for the other tables.

7 0
2 years ago
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belka [17]

f(x) = -(3x + 9) - 13\\f(-5) = -(3 \cdot (-5) + 9) - 13\\= -(-15 + 9) - 13\\= -(-6) - 13\\= 6 - 13\\= - 7

8 0
3 years ago
In the diagram below, GH is parallel to DE . If GH is 3 more than EH FH=10, and DE=12 find the length of EH. Figures are not nec
steposvetlana [31]

Answer: 5

Step-by-step explanation:

Since \overline{GH} \parallel \overline{DE}, by the corresponding angles theorem, \angle FGH \cong \angle FDE, \angle FHG \cong \angle FED. This means \triangle FGH \sim \triangle FDE by AA.

As corresponding sides of similar triangles are proportional,

\frac{10}{x+3}=\frac{10+x}{12}\\(10)(12)=(10+x)(x+3)\\120=x^{2}+13x+30\\x^{2}+13x-90=0\\(x+18)(x-5)=0\\x=-18, 5
However, as distance must be positive, we consider the positive solution, x=5.

Therefore, the answer is <u>5</u>

6 0
2 years ago
X2+5x=3x+11 and solve by completing the square
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x^2+5x=3x+11\\&#10;x^2+2x-11=0\\&#10;x^2+2x+1-12=0\\&#10;(x+1)^2=12\\&#10;x+1=\sqrt{12} \vee x+1=-\sqrt{12}\\&#10;x=-1+2\sqrt3 \vee x=-1-2\sqrt3
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4 years ago
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