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Alisiya [41]
3 years ago
10

Find the specified amount for the investment:$5,000.00 invested at 8.1% compounded quarterly; find the account balance at the en

d of 5 years.
Answer: $________
Mathematics
2 answers:
Airida [17]3 years ago
7 0

Answer:

0.081

Step-by-step explanation:

Oliga [24]3 years ago
5 0

Answer:

zidiFind the specified amount for the investment:$5,000.00 invested at 8.1% compounded quarterly; find the account balance at the end of 5 years.

Answer: $________

Step-by-step explanation:

Find the specified amount for the investment:$5,000.00 invested at 8.1% compounded quarterly; find the account balance at the end of 5 years.

Answer: $________Find the specified amount for the investment:$5,000.00 invested at 8.1% compounded quarterly; find the account balance at the end of 5 years.

Answer: $________

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What number does y stand for in this equation?<br> 2y - 7 = 35
timama [110]

Answer:

y stands for 21 in this equation.

Step-by-step explanation:

2y - 7 = 35

2y = 42

y = 21

3 0
3 years ago
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garik1379 [7]
D,A,B,C i think this is correct !
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BaLLatris [955]
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3 years ago
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Does anyone know the minim value of the function f(x) =2x^2 -4x -6?. I’m online due to my quarantine and am looking for extra he
navik [9.2K]

Answer:

f(x) = - 8

Explanation:

The given function is

f(x) =2x^2 -4x -6

The first step is to find the derivative of the function. Recall, if

y = ax^b

y' = abx^(b - 1)

Thus,

f'(x) = 4x - 4

We would equate f'(x) to zero and solve for x. We have

4x - 4 = 0

4x = 4

x = 4/4

x = 1

We would substitute x = 1 into the original function and solve for f(x) or y. It becomes

f(1) =2(1)^2 -4(1) - 6 = 2 - 4 - 6

f(1) = - 8

Thus, the minimum value is f(x) = - 8

4 0
1 year ago
In a population of 1000 snails, tests of snail color genes show that 160 snails are AA, 480 are Aa and 360 are aa. What is the f
Kipish [7]

Answer:

Option C.

Step-by-step explanation:

Total population = 1000 snails

AA = 160 snails

Aa = 480 snails

aa = 360 snails

Frequency of each type.

AA=\dfrac{160}{1000}=0.16

Aa=\dfrac{480}{1000}=0.48

aa=\dfrac{360}{1000}=0.36

Now, we get

A^2=0.16\Rightarrow A=\sqrt{0.16}=0.4

he frequency of the A allele in this population is 0.4.

Therefore, the correct option is C.

3 0
3 years ago
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