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3 years ago

Daisy is building a rectangular pen for her chickens along one wall in her back yard. She needs to build a fence

Mathematics

1 answer:

frosja888 [35]3 years ago

7 0

Answer:

Daisy has one side of the rectangular pen along the wall, so she needs one width, w, and two lengths, 2ℓ. She has at most 125 feet of fencing materials to build the fence for her pen

1 second/24 frames

so if he started with 0 frames

time s = (1/24) (additional f)

but he already had at least 250 frames

time s = (1/24)( f-250) or maybe less time if he had more than 250

24 s </= f - 250

f >/= 24 s + 250

Step-by-step explanation:

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How do you divide fractions

krek1111 [17]

When dividing fractions, " flip " what u r dividing by, then multiply
Examples :
(2/3) / (4/5) = 2/3 * 5/4 = 10/12 reduces to 5/6

8 / (1/5) = 8 * 5/1 = 40

(1/3) / 7 = 1/3 * 1/7 = 1/21

just make sure u " flip " the number u r dividing by and not the other one

7 0

3 years ago

Can you please help we with this a/5 -23 = -25

Elden [556K]

To find the value for a in this equation, we can follow the next steps:

$\frac{a}{5}-23=-25$

First, multiply all of the equation by 5:

$5\cdot(\frac{a}{5}-23=-25)\rightarrow\frac{5}{5}\cdot a-115=-125\rightarrow a-115=-125$

Finally, add 115 to both sides of the equation:

$a-115+115=-125+115\rightarrow a+0=-10\rightarrow a=-10$

Therefore, the value for a is a = -10.

7 0

1 year ago

Alonso brings $21 to the market to buy eggs and avocados. He gets eggs that cost $2.50. Then, he notices

ELEN [110]

Answer:

2.50 + 5B ≤ 21;

Step-by-step explanation:

Cost of eggs = $2.50

Cost of avocado = $5 (bag of 3)

Total budgeted amount = $21

Bags of avocado = B

Therefore :

(Cost of eggs + cost of avocado) ≤ total budgeted amount

($2.50 + $5(B)) ≤ 21

2.50 + 5B ≤ 21

5B ≤ 21 - 2.50

5B ≤ 18.50

B ≤ 18.50 / 5

B ≤ 3.7

Therefore the maximum number of bags can purchase is 3(whole number without exceeding $21)

5 0

3 years ago

Read 2 more answers

A sample of 100 wood and 100 graphite tennis rackets are taken from the warehouse. if 13 wood and 10 graphite are defective and

Nimfa-mama [501]

Let's split the problem in non-intersecting subsets: we have $87$ good wood racquets, $13$ defective wood rackets, $90$ good graphite racquets, $10$ defective graphite rackets.

The probability that the racket is wood or defective covers the following subsets: good wood, defective wood and defective graphite, which have, respectively, $87$ , $13$ and $10$ elements.

Since the total is $200$ elements, the probability is

$\frac{87+13+10}{200} = \frac{110}{200} = 0.55$

8 0

3 years ago

2a = 8<br> 4b = 0<br> 5c = 35<br> x/2 = 8

Furkat [3]

A=4
B=0
C=7
X=16
This is what I think

3 0

3 years ago

Read 2 more answers