Answer:
Step-by-step explanation:
Find AOS
X = -b/2a
X = -65/2(-14)
X = -65/-28
X = 2.32 secs
t = 2.32secs
A) y value when t = 2.32 is the maximum height.
Substitute t in the equation.
h(t)= -14t^2+65t+1.75
h(t)= (-14 * 2.32²) + (65 * 2.32) + 1.75
= (-14 * 5.38 ) + (65 * 2.32) + 1.75
= -75.35 + 150.8 + 1.75
= 77.2 ft
Maximum height attained by the ball = 77.2 ft
B) Time the maximum height achieved = 2.32secs
C) The ball off of the ground when it was shot is well t = 0
Substitute t in equation
h(t)= -14t^2+65t+1.75
h(0)= (-14 * 0²) + (65 * 0) + 1.75
= 0 + 0 + 1.75ft
The ball is 1.75ft off the ground when it was shot.
Answer:
It means that the roots of the quadratic equation are real and distinct
Step-by-step explanation:
Here, given the discriminant of the quadratic equation, we want to find out the nature of the solutions.
Mathematically, we can use to determine the nature of the discriminant.
By it’s formula;
D = b^2 - 4ac
We can see that the given discriminant 40 is a positive value. What this means is that the quadratic equation has roots which are real and are distinct
Answer:
after 3 half lives the amount should be reduced to 19.375g
Step-by-step explanation:
after the first half life , amount left =
155÷2
= 77.5g
2nd half life
77.5÷2
=38.75g
3rd Half life
38.75÷2
=19.375g
360 because the sides are 120, 130, 60, and 50
The standard form of a line is given by -
where
- A= integer
- x = x-intercept
- B= integer
- y = y-intercept
- C = constant
<h3><u>Given Equation: - </u></h3>
Arranging equation in standard form -
Comparing with standard form of line -
Thus , 5 is our required answer.
