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MArishka [77]
2 years ago
10

PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!!

Mathematics
1 answer:
baherus [9]2 years ago
8 0

httrybeghtvfrgbey MB dnsytbebwf33566

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Solve for the hypotenuse in the right triangle shown.​
N76 [4]

Answer:

Square root of 34

Step-by-step explanation:

a^2 +b^2 =c^2

3^2 + 5^2 = 34

\sqrt{34}

4 0
2 years ago
Cos 4θ − cos 2θ = sin θ
hichkok12 [17]
cos(4\theta) - cos(2\theta) = sin(\theta)
-2sin(\frac{4\theta + 2\theta}{2})sin(\frac{4\theta - 2\theta}{2}) = sin(\theta)
-2sin(\frac{6\theta}{2}sin\frac{2\theta}{2}) = sin(\theta)
-2sin(3\theta)sin(\theta) = sin(\theta)
\frac{-2sin(3\theta)sin(\theta)}{-2sin(\theta)} = \frac{sin(\theta)}{-2sin(\theta)}
sin(3\theta) = -\frac{1}{2}
sin^{-1}[sin(3\theta)] = sin^{-1}(-\frac{1}{2})
3\theta = -30
\frac{3\theta}{3} = \frac{-30}{3}
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7 0
2 years ago
Please help me with this
Slav-nsk [51]

Answer:

21.....

Step-by-step explanation:

hope this helps

7 0
2 years ago
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Which statement is true?
WITCHER [35]

Answer: bro its the last one

Step-by-step explanation:

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2 years ago
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7. If U= {2, 4, 6, 8, 10, 12, 14, 16} and<br> A = {6, 10, 14}, what is A'?
Tresset [83]

The compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

We are given the universal set as:

U = {2, 4, 6, 8, 10, 12, 14, 16}

We are also given that set A is:

A = {6, 10, 14}

We need to find A'

For this, we will subtract set A from the universal set, U.

So, we get that:

A' = U - A

A' = {2, 4, 6, 8, 10, 12, 14, 16} - {6, 10, 14}

Solving the expression, we get that:

A' = {2, 4, 8, 12, 16}

Therefore, we get that, the compliment of set A that is A' is equal to {2, 4, 8, 12, 16}.

Learn more about sets here:

brainly.com/question/2166579

#SPJ9

5 0
9 months ago
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