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guapka [62]
3 years ago
13

-3/4.-5/7 = -15/28 Do you agree with Noah's answer? Explain why or why not.

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer: Yes

Step-by-step explanation: Simply multiply the numerators and denominators separately:

artcher [175]3 years ago
6 0

Answer:

no

Step-by-step explanation:

because -3/4- 5/7= -41/28 and when simplified it is -1 13/28

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A triangle has a height of 15 in. and a area of 120 in. What is the length of it's base?
jek_recluse [69]

Answer:

b=16

Step-by-step explanation:

Formula~ 1/2*b*h

1/2*15*b=120

7.5b=120

b=120/7.5

b=16

(you can substitute the value to check-i've done it below)

1/2*16*15=?

if you work it out, the ans will be 120, therefore the ans is correct!

7 0
3 years ago
Oliver bought a scarf that costs 8 dollars and a watch that costs 9 dollars. At the counter he received a discount. If he paid o
Alex787 [66]

Answer: 4

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3 years ago
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yawa3891 [41]

Answer:

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6 0
3 years ago
Read 2 more answers
Perfect squares are closed under multiplication true or false
Viefleur [7K]

Answer:

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Step-by-step explanation:

5 0
4 years ago
Please help thank you.
MA_775_DIABLO [31]
Question 1:

To start off this question, we can tell that this is a square because it has 4 right angles and 4 congruent sides.

A square has four parallel sides and 4 congruent sides, so a square is a rhombus and parallelogram. 

A square has 4 right angles, so it's also a rectangle.

A square has 4 sides, so it's also a quadrilateral.

The first choice is your answer.

Question 2:

Not all quadrilaterals are rectangles, so A is incorrect.

Not all quadrilaterals are squares, so B is incorrect.

All rectangles are types of quadrilaterals, so C is correct.

Not all quadrilaterals are parallelograms, so D is incorrect.

Thus, C is your answer.

Question 3: 

The first choice will not work because a rhombus will satisfy those conditions, and a rhombus is not always a square.

The second choice will work because only a square will satisfy that condition because only squares have 4 congruent sides along with equal diagonals.

Thus, the second choice is your answer.

Have an awesome day! :)
7 0
4 years ago
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