All categories

3 years ago

HELP ASAP PLEASE & THANK U!!!!

Mathematics

1 answer:

Vera_Pavlovna [14]3 years ago

5 0

Answer:

1. (1, -3.5)

2. (-9, 25) *note, there is a typo in the question, please ask your teacher about this

Step-by-step explanation:

Use the midpoint formula to calculate the midpoint.

Use the formula to find the end point, and double the distance between your endpoint and midpoint to find the other endpoint.

Since the distance between the x coordinate is 8 (from -1 to 7), then the other endpoint is 8 away from -1, or -9.

please give thanks :)

You might be interested in

Geometry help! Picture included :)

AURORKA [14]

Set up a proprtion and cross multiply.

18/7.5=22/4x+1

7.5×22=18 (4x+1)
165=72x+18
147=72x
x=2.04

8 0

4 years ago

True or False: If we have an integer primal solution with cost C and a fractional dual solution with cost at least C/2, the size

maria [59]

Answer:

True

Step-by-step explanation:

The size of the vertex cover is atleast twice the size of the maximum edge. Vertex must contain atleast one vertex from the matched edge. Vertex are never the strong dual solutions of each other.

3 0

3 years ago

If the graph of the following parabola is shifted two units left and three units down, what is the resulting equation?

mafiozo [28]

Answer:

$x=-8\left(y+3\right)^2-2$

Step-by-step explanation:

Because the x and y have been reversed in this equation, shifting the parabola to the left will be outside of the exponent and shifting up and down will be inside with the exponent.

The equation becomes $x=-8\left(y+3\right)^2-2$ .

Where subtracting by 2 moves it two units to the left and adding by 3 moves it 3 units down.

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

3 years ago

If a student has a monthly income of about $250, how much do you predict he might spend on clothing in a month?

yaroslaw [1]

Answer:

80$

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers