Lets write as an equation the info provided in the problem:
original area = 200*300 = 60000 squared meters
Adding x meters to the length is: 300 + x
Adding x meters to the width is: 200 + x
If the area doubles in size we have: 2*<span>60000
Now writing as a single equation all info:
(300 + x)(200 + x) = 120000
We have to make the operations and solve:
60000 + 300x + 200x + x^2 = </span><span>120000
x^2 + 500x - 60000 = 0
This is a squared trinomial, to solve it we need two numbers that subtracted give us 500 and multiplied -60000:
(x + 600)(x -100) = 0
So there are two solutions, x = -600 and x = 100, we choose the positive one:
x = 100
thererefore the value of x is 100 meters</span>
The vertices of AMNO are M (1,3), N (4,9), and O (7,3). The vertices of APQR are P (3,0), Q (4,2), and R (5,0) Which conclusion
Pavel [41]
Answer:
the correct answer should be C
Step-by-step explanation:
hope this helps you
The answer would be:
y = 5
x = 4
Answer:
y=29
Step-by-step explanation:
y=5+6(4)
y=5+24
y=29
BRAINLIEST PLZ
