Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
<h3>
How many liters of each solution do we need to use?</h3>
First, we need to define the variables:
- x = liters of the 35% acid used.
- y = liters of the 80% acid used.
We know that we want to produce 60 liters of 65% acid, then we have the system of equations:
x + y = 60
x*0.35 + y*0.80 = 60*0.65
(in the second equation we wrote the percentages in decimal form).
To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:
x = 60 - y
Replacing that in the other equation:
(60 - y)*0.35 + y*0.80 = 60*0.65
y*(0.80 - 0.35) = 60*(0.65 - 0.35)
y*0.45 = 60*0.30
y = 60*0.30/0.45 = 40
So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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To get the price of the new item after an increase of 10% you would have to find 10% of whatever the price is and add it to the original price so for example say the price is $300 you would do 300*0.10(0.10 is 10%) which is 30 and add that to 300 so the new price would be $330
Answer:
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Answer:
A (3/2, 9/2)
Step-by-step explanation:
Let's take the first solution which is (3/2 , 9/2). If we substitute 3/2 into x we get the equation (3/2)^2 we get y as 9/4 not 9/2, therefore (3/2 , 9/2) does not lie on the curve y = x^2
