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3 years ago

Bobby has 3/4 of a bag of chips.He

Mathematics

1 answer:

lidiya [134]3 years ago

6 0

Answer:

7/12

Step-by-step explanation:

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Find an equation for a line that is normal to the graph of y=xe^x and goes through the origin

Marina CMI [18]

Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin

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If these two shapes are similar, what is the measure of the missing length x?

Rus_ich [418]

Answer:

$x=22\ yd$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

$\frac{x}{14}=\frac{77}{49}$

solve for x

$x=\frac{77}{49}(14)$

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3 years ago

Write an equation of the line that passes through (18,2) and is parallel to the line 3y-x=-12 .

uysha [10]

Answer:

$y = \frac{1}{3}x-4$

Step-by-step explanation:

Step 1: Solve for y in the first equation

$3y - x = -12$

$3y - x + x = -12 + x$

$\frac{3y}{3} = \frac{x}{3} - \frac{12}{3}$

$y = \frac{1}{3}x - 4$

Step 2: Determine the important aspects

We know that our line is parallel to the other line that has a slope of 1/3 which means that our slope is also going to be 1/3. We also know that our line crosses the point (18, 2) which means that we can use the point slope form to determine our equation

Point Slope Form → $(y-y_1) = m(x - x_1)$

Step 3: Plug in the information and solve

$(y-2) = \frac{1}{3}(x - 18)$

$y - 2 = \frac{1}{3}x - 6$

$y - 2 + 2 = \frac{1}{3}x - 6 + 2$

$y = \frac{1}{3}x-4$

Answer: $y = \frac{1}{3}x-4$

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2 years ago