The mean increases when the outlier is removed
Teacher c makes the most money at the end of their career since the model is entirely linear.
Answer:
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Step-by-step explanation:
y = (x^2 - 3)^sinx
ln y = ln (x^2 - 3)^sinx
ln y = sin x * ln (x^2 - 3)
1/y * dy/dx = sin x * {1 / (x^2 - 3)} * 2x + ln(x^2 - 3) * cos x
1/y dy/dx = 2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)
dy/dx = [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)] * y
dy/dx = (x^2 - 3)^sin x [2x sin x/ (x^2 - 3) + cos x ln(x^2 - 3)]
Let the total earnings be = x
Jennifer and Chris split the earnings in the ratio 3:2
Jennifer earned = $48


x=80
Hence total earnings are $80
(a) Chris earning is = 
Hence, Chris earns $32
(b) Jennifer spends 30% of her earnings on a book.
So, price of the book = 
Price of book = $14.40
(c) Jennifer also buys a magazine for = $5.40
So, total money Jennifer spent on book and magazine = 14.40+5.40=19.80
Money left with Jennifer = 48-19.80= $28.20
In fractions =
or multiplying the numerator and denominator by 10, we get
=
(d) Let the original price of the shirt = x
reduction percentage on x= 40%
Price paid after reduction = 16.80



Hence, the original price of the shirt was $42.