DOMAIN:
- Set of allowable inputs (set of 1st elements of the ordered pairs in relation)
- X point
- AKA the input
DEFINE INPUT:
A number that'll be used in a function rule to determine the value of the output
RANGE:
- Set of possible outputs (set of 2nd elements of the ordered pairs in relation)
- Y point
- AKA the output
DEFINE OUTPUT:
Result of applying a function rule to the value of ani input
ORDERED PAIRS:
(-1, 7): -1 is the domain & 7 is the range
(3, 5): 3 is the domain & 5 is the range
(4, 9): 4 is the domain & 9 is the range
(-6, -10): -6 is the domain & -10 is the range
(-2, 8): -2 is the domain & 8 is the range
Hope this helps you!!! :)
Move the discount sign two places to the left and divide the regular price by that decimal. Then take that price and put it in the selling price and take the selling price and subctract that from the original price
Answer:

Step-by-step explanation:
we can easily calculate the perimeter of three points, using vectors. See the picture...
BRYAN would need to buy 3 gallons and 8 quarts witch would cost
$14.99 times 3 and $4.99 times 8
$44,97+$39.92=$84.98 would be spent for all off the paint he needs
Answer:

So it would takes approximately 6.9 hours to reach 32 F.
Step-by-step explanation:
For this case we have the following differential equationÑ

We can reorder the expression like this:

We can use the substitution
and
so then we have:

IF we integrate both sides we got:

If we apply exponential in both sides we got:

And if we replace w = u-T we got:

We can also express the solution in the following terms:

For this case we know that
since w ehave a cooloing,
, we have this model:
And if we want that the temperature would be 32F we can solve for t like this:



If we apply natural logs on both sides we got:


So it would takes approximately 6.9 hours to reach 32 F.