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Softa [21]
3 years ago
12

Find the zeros of the quadratic function f(x) = 2x2 - 8x + 6 from the graph

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0

Answer: X=3,1

The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x

Step-by-step explanation: Have a nice day

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3-2(x + 1)=2x-7<br> SOLVE AND HOW MANY SOLUTIONS ?
jekas [21]

Answer:

2

Step-by-step explanation:

3−2(x+1)=2x−7

3+(−2)(x)+(−2)(1)=2x+−7(Distribute)

3+−2x+−2=2x+−7

(−2x)+(3+−2)=2x−7(Combine Like Terms)

−2x+1=2x−7

−2x+1=2x−7

Step 2: Subtract 2x from both sides.

−2x+1−2x=2x−7−2x

−4x+1=−7

Step 3: Subtract 1 from both sides.

−4x+1−1=−7−1

−4x=−8

Step 4: Divide both sides by -4.

−4x−4=−8−4

x=2

5 0
3 years ago
Which equations are true for x = –2 and x = 2? Check all that apply.
4vir4ik [10]
А. х²-4=0; х²=4; х=±2, true. B. x²=-4; there is no solution. C. 3x²+12=0; 3x²=-12; x²=-4; there is no solution. D. 4x²=16; x²=4; x=±2, true. E. 2(x-2)²=0; 2(x²-4x+4)=0; 2x²-8x+8=0; x²-4x+4=0; x1=2; x2=2. False. The answer: A, D.
4 0
3 years ago
Express the confidence interval (0.432, 0.52 in the form of ±<br> e.
lakkis [162]
For a known standard deviation, the confidence interval for sample size = n is
(x-z \frac{ \sigma }{ \sqrt{n}},x+x \frac{ \sigma }{ \sqrt{n} }  )
where
x =  average
n = sample size
\sigma = stad. deviation
z = contant that reflects confidence interval

Let a = x
Let b = z \frac{ \sigma }{ \sqrt{n} }

From the given information,
a - b = 0.432          (1)
a + b = 0.52           (2)

Add (1) and (2): 2a = 0.952  =>  a = 0.476
Subtract (2) from (1): -2b = -0.088  => b = 0.044

Therefore, the confidence interval may be written as
(0.476 - 0.044, 0.476 + 0.044), or as
(0.476 \pm 0.044)

4 0
3 years ago
Which of the following sets of points does NOT represent a function?
QveST [7]
1 does not represent a function
6 0
3 years ago
Please can someone solve this
Crazy boy [7]

Answer:

200.86

Step-by-step explanation:

Using the formulas:

A=πr2

C=2πr

Solving for A:

A=C2

4π=50.242

4·π≈200.85812

I hope this helps.

4 0
3 years ago
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