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barxatty [35]
2 years ago
14

Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 2x − 4x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a

nd c3 so that g(x) = 0 on the interval (−[infinity], [infinity]). If a nontrivial solution exists, state it. (If only the trivial solution exists, enter the trivial solution {0, 0, 0}.) {c1, c2, c3} = $$ Correct: Your answer is correct. Determine whether f1, f2, f3 are linearly independent on the interval (−[infinity], [infinity]).
Mathematics
1 answer:
bekas [8.4K]2 years ago
7 0

9514 1404 393

Answer:

  • (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
  • NOT linearly independent

Step-by-step explanation:

We want ...

  c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0

Substituting for the fn function values, we have ...

  c1·x +c2·x² +c3·(2x -4x²) ≡ 0

This resolves to two equations:

  x(c1 +2c3) = 0

  x²(c2 -4c3) = 0

These have an infinite set of solutions:

  c1 = -2c3

  c2 = 4c3

Then for any parameter t, including the "trivial" t=0, ...

  (c1, c2, c3) = (-2t, 4t, t)

__

f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)

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Do looks matter when is comes to guys​
jenyasd209 [6]

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Step-by-step explanation:

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In a class the ratio of boys to girls is 4:3 30% of the boys are left handed.
alex41 [277]
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6 0
3 years ago
A surveyor leave her base camp and drive 42 km on a bearing of 032, she then drive 28km on a bearing of 154.How far is she then
aleksklad [387]

Answer:

Step-by-step explanation:

The scenario is represented in the attached photo. Triangle ABC is formed. AB represents her distance from her base camp. We would determine BC by applying the law of Cosines which is expressed as

a² = b² + c² - 2abCosA

Where a,b and c are the length of each side of the triangle and B is the angle corresponding to b. It becomes

AB² = AC² + BC² - 2(AC × BC)CosC

AB² = 42² + 28² - 2(42 × 28)Cos58

AB² = 1764 + 784 - 2(1176Cos58)

AB² = 2548 - 1246.37 = 1301.63

AB = √1301.63

AB = 36.08 km

To find the bearing, we would determine angle B by applying sine rule

AB/SinC = AC/SinB

36.08/Sin58 = 42/SinB

Cross multiplying, it becomes

36.08SinB = 42Sin58

SinB = 42Sin58/36.08 = 0.987

B = Sin^-1(0.987)

B = 81°

Therefore, her bearing from the base camp is

360 - 81 = 279°

8 0
3 years ago
If f(x) = (x + 9 and g(x) = --6, which describes the range of (f + g)(x)?
S_A_V [24]

Given:

Consider the below figure attached with this question.

To find:

The value of (f+g)(x).

Solution:

The given functions are:

f(x)=|x|+9

g(x)=-6

Now,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=|x|+9+(-6)

(f+g)(x)=|x|+9-6

(f+g)(x)=|x|+3

We know that,

|x|\geq 0

Adding 3 on both sides, we get

|x|+3\geq 0+3

(f+g)(x)\geq 3

So, (f+g)(x)\geq 3 for all values of x.

Hence, the correct option is A.

6 0
3 years ago
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