Answer:
-2.4
-0.8
0.2
0.9
1.6
Step-by-step explanation:
I just know.
1) We can determine by the table of values whether a function is a quadratic one by considering this example:
x | y 1st difference 2nd difference
0 0 3 -0 = 3 7-3 = 4
1 3 10 -3 = 7 11 -7 = 4
2 10 21 -10 =11 15 -11 = 4
3 21 36-21 = 15 19-5 = 4
4 36 55-36= 19
5 55
2) Let's subtract the values of y this way:
3 -0 = 3
10 -3 = 7
21 -10 = 11
36 -21 = 15
55 -36 = 19
Now let's subtract the differences we've just found:
7 -3 = 4
11-7 = 4
15-11 = 4
19-15 = 4
So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.
3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2
Answer:

Step-by-step explanation:
![\frac{2{x}^{2} - 5x - 3}{2x + 1} = \frac{[x - 3][2x + 1]}{2x + 1} = x - 3](https://tex.z-dn.net/?f=%5Cfrac%7B2%7Bx%7D%5E%7B2%7D%20-%205x%20-%203%7D%7B2x%20%2B%201%7D%20%3D%20%5Cfrac%7B%5Bx%20-%203%5D%5B2x%20%2B%201%5D%7D%7B2x%20%2B%201%7D%20%3D%20x%20-%203)
This is much faster than doing long-polynomial division, which we could have done, since the divisor is not in the form of <em>x</em><em> </em><em>-</em><em> </em><em>c,</em><em> </em>where<em> </em><em>−</em><em>c</em><em> </em>gives gives the OPPOSITE TERMS OF WHAT THEY REALLY ARE.
I am joyous to assist you anytime.
Answer:
y = 2x + 20


Step-by-step explanation:
Vlad spent 20 minutes on history. Then Vlad spent 2 minutes on each math problem for homework, this is 2x. So in total, he spent 20+2x on homework. Depending on how many problems he did, the total time y can be found. This is the equation 20+2x=y.
If Vlad did 0 math problems then he spent at least 20 minutes on homework from history. This is the constraint
.
We also know Vlad can do many math problems but the least amount he did was 0, so the second constraint is
.