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Juli2301 [7.4K]
3 years ago
11

Solve each absolute value inequality. Graph the solution. 2 ≤ |x| − 8

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
7 0
I don’t know I just want your points
Viktor [21]3 years ago
4 0

Answer:

Step-by-step explanation:

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If n = 11 and p = 5 what is the value of the expression 18 - n - 2 + p
yan [13]

Answer:

10

Step-by-step explanation:

If n = 11 and p = 5, we can just substitute the values in for n and p in the equation 18 - n - 2 + p.


The new equation would be 18 - 11 - 2 + 5.

Using PEMDAS, we get the answer of 10.  

18 - 11 = 7

7 - 2 = 5

5 + 5 = 10


Hope this helps!

3 0
2 years ago
8÷2(2+2). I need help finding the correct answer. 8÷2(2+2). I need help finding out if it is 1 or 16.
deff fn [24]

Answer:

The answer is 16

Step-by-step explanation:

8 divided by 2 (2+2)=16

8 0
3 years ago
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HELPP ME PLZ WILLING TO SEND MONEY! It’s urgent
ExtremeBDS [4]

Answer:

I think it would be 5 and 5 of each solution

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3 years ago
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what will come in the following series 20 25 23 28 26 31 29 34 _? answer is 31. please explain how?? urgent pls​
Assoli18 [71]

The series of numbers is adding 5 and then subtracting 2

20+5=25

25-2=23

23+5=28

28-2=26

and so on. Do you understand?

7 0
3 years ago
Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}
Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

<h3>   </h3>
  • To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by \large \sf a^{n}. The terms of a power are:

<h3>     </h3>
  • Base
  • Exponent
  • equal factors
  • power
<h3>         </h3>

✏️ <u>Resolution/Answer</u>:

\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\

  • Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-4\cdot4\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4^{2}}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 4\cdot4}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=\\\\

  • <em>Multiply </em>the power at denominator of the fraction:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4\cdot4}=

\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=\\\\

  • <em>Multiply </em>the numerator numbers together:

\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=

\large \sf \dfrac{-16\cdot16\cdot 256     }{16}=

\large \sf \dfrac{-256\cdot 256     }{16}=

\large \sf \dfrac{- 65536  }{16}=\\\\

  • Simplify the fraction by number 16:

\\\large \sf \dfrac{- 65536  }{16}=

\large \sf \dfrac{- 65536  \div16}{16\div16}=

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}} \\\\\\

  • So this expression in its simplified form = -4096/1 or -4096.

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1}  \ or \ -4096 }}}}}}\\\\

                                 ★ Hope this helps! ❤️

6 0
3 years ago
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