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ahrayia [7]
3 years ago
5

Find the midpoint of the line segment shown below.

Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

x²-6x+y²-4y=-4

Step-by-step explanation:

We know the circle equation stands like this:

(x-a)² + (y-b)² = R²

and (a,b) is center

and R stands for Radius

so in this case:

center = (3,2)

R = 3

So

(x-3)² + (y-2)² = 9

x²-6x+9 + y²-4y+4=9

x²-6x+y²-4y=-4

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3 years ago
2/5 - (-4/3) = what does it equal because im really confused
ira [324]

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26/15

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(HELP PLEASE) if f(x)=x/3-2 and g(x)=3x^2+2x-6 , find (f+g)(x)
lukranit [14]
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Next, ident. and sum up the x terms:  Result:  (1/3  +  2) = (7/3)x
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8 0
3 years ago
Read 2 more answers
Please help! Correct answers only please!
gulaghasi [49]

Answer:

1/4

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7 0
3 years ago
Solve the following: 2(6x + 5) = 94
Black_prince [1.1K]

Answer: x=7

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2(6x+5)=94

(2)(6x)+(2)(5)=94(Distribute)

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Step 2: Subtract 10 from both sides.

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Step 3: Divide both sides by 12.

12x

12

=

84

12

x=7

6 0
3 years ago
Read 2 more answers
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