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lisov135 [29]
3 years ago
6

338 to the nearest ten

Mathematics
2 answers:
vodomira [7]3 years ago
8 0
The answer for 338 to the nearest ten is 340
Akimi4 [234]3 years ago
6 0
138 to the nearest 10th 100 30 8 30 is the 10th Around 810 to 30 you come out with 40 your answer is 140
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Can someone help me and do it step by step
Tema [17]

Answer:

4

Step-by-step explanation:

65-25=40

40/10=4

6 0
3 years ago
On a 16 scale drawing of a bike, one part is 3 inches long. How long will the actual bike part be?
Oksanka [162]
Multiply 16*3 to get 48, the bike is 48 units so 16:1,16/1=16. So the answer would be 16. Hope I helped! 
4 0
3 years ago
Read 2 more answers
The square root of the quotient of a number n and 3 is equal to the square root of 4 less than the number. Which of the followin
Lisa [10]

Answer:

6

Step-by-step explanation: You can set up the equation: \sqrt{\frac{n}{3} } = \sqrt{n-4} You square both sides to cancel out the squares which leaves you with \frac{n}{3} = n - 4. Then you just solve as normal which ends you up with an answer of 6. You can check this by plugging 6 back into the equation and see that you end up with \sqrt{2} on both sides.

4 0
3 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
What’s the perimeter lol
meriva

Answer:

try 47 im not sure tho ........

3 0
3 years ago
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