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3 years ago

Which equation is equivalent to the given equation?

Mathematics

2 answers:

Zolol [24]3 years ago

7 0

Answer:

i guess so

$\\ \\ \\$

Anni [7]3 years ago

6 0

<h2>Answer: x² + 15x + 50 </h2>

<h3>Step-by-step explanation:</h3>

Since all the options is a quadratic = 0, then let's write the given equation in that form by making 0 the subject of the equation:

−x² = 15x+50 <em> [add x² to both sides]</em>

-x² + x² = x² + 15x + 50 <em> [simplify]</em>

<h3> x² + 15x + 50 = 0 (OPTION D)</h3>

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Jared surf for one third of the nine hours he was at the beach he spent the rest of the time building a sandcastle how many hour

WINSTONCH [101]

9 dived by 3 = 3
so he surfed for 3 hours = 1/3 of 9
and there are 6 hours left

so he spent 6 hours building a sandcastle

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3 years ago

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I need help on this math problem.

OLEGan [10]

B: (0, a)

C should have the same y value as B

D: (a,0)

C should have the same x value as D

So point C is (a,a)

Since point A is on the origin, its point is (0,0)

You use the slope formula and plug in point A and C:

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3 years ago

A customer member owe 16.50 and pays $20 in cash the change due is 3.50 provide the amount owe using the smallest number of bill

Daniel [21]

Answer:

Step-by-step explanation:

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3 years ago

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A cheetah can run at its top speed for about 25 seconds. Complete the table to represent a cheetah running at a constant speed.

olchik [2.2K]

Answer:

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If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

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3 years ago