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gregori [183]
2 years ago
14

(6+9)2+6(600-9)+600 divide 30

Mathematics
2 answers:
Evgesh-ka [11]2 years ago
8 0

Step-by-step explanation:

GIVEN

HERE

= 6+9+2+6+600÷30 { firstly add numbers }

= 623 ÷ 30

= 20

I think you understand

scoray [572]2 years ago
4 0
20 simple math , pretty easy
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The sum of two numbers is 5. The difference of two numbers is -1. Find the numbers
Drupady [299]

Answer:

The numbers are 2 and 3.

Step-by-step explanation:

The smaller number would have been 1 less than the bigger number so that if for example the smaller number is 1 and the bigger number is 2, their difference would have been 1-2 = -1

5 is an odd number so if it were to be divided into two integers, one would be more than the other, namely 2 and 3.

If you double-check their difference:

2-3 = -1

Thus, the two numbers are 2 and 3.

6 0
3 years ago
Read 2 more answers
Help me answer question #1
konstantin123 [22]
A. The expression has two factors.
The two factors of the expression 7(2x+5) are 7 and (2x+5).
Hope this helps. 
4 0
4 years ago
Solve question for me please​
mixer [17]

Answer:

C

Step-by-step explanation:

Circumference is found using the formula C = \pi d and here d = 16. To find it, substitute 16 into the formula and simplify.

C = \pi d\\C= \pi (16)\\C= 50.24

3 0
3 years ago
Marcel has $40 to spend on amusement park rides. Tickets cost $1.50 without special membership pass, or $1.25 with a membership
aniked [119]
He should, because he would get two more tickets.  

To prove this, do this:
Divide $40 by 1.5 to get 26.6666666666666666667 (Ignore the .666666666667, just use 26 because you can't buy part of a ticket.)

Now subtract 5 from $40 to get the amount with the membership pass. You will get 35.  Divide 35 by 1.25 to get 28.  Marcel will get 2 more tickets if he buys the pass.

6 0
3 years ago
Read 2 more answers
If $3000 is deposited in an account that pays 5% interest, what is the difference in the amount after 4 years between the amount
Triss [41]
\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$3000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
t=years\to &4
\end{cases}
\\\\\\
A=3000(1+0.05\cdot 4)\implies \boxed{A=3600}\\\\
-------------------------------\\\\

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &4
\end{cases}

\bf A=3000\left(1+\frac{0.05}{1}\right)^{1\cdot 4}\implies A=3000(1.05)^4\implies \boxed{A=3646.51875}\\\\
-------------------------------\\\\
\stackrel{\textit{compounded interest}}{3646.51875}~~-~~\stackrel{\textit{simple interest}}{3600}
7 0
4 years ago
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