<span>6(2x-4y)=3(2x+4)
(2x-4y)=3/6(2x+4)
2x-4y=1/2(2x+4)
2(x-2y)=1/2x2(x+2)
x-2y=1/2(x+2)
x-2y=1/2x+1
x-1/2x=1+2y
x/2-1=2y
y-y1=m(x-x1) that is slope point intercept form
now plugin some points and get according y values so u can graph</span><span />
Answer:
The answer at the letter 90
Answer:
Horizontal asymptote of the graph of the function f(x) = 25/1+4x is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0. There is also a <em>vertical</em> asymptote at x=-1/4
When denominator's degree (1) is higher than nominator's degree (0) then the horizontal asymptote is y=0
Answer:5
Step-by-step explanation: