The expected gain or loss is an illustration of mean and expected values.
The expected total gain is 83 points
The given parameters are:
- Addition of 20 points for rolling a 6
- Removal of 3 points for not rolling a 6
The probability of rolling a 6 in a fair die is 1/6.
The probability of not rolling a 6 in a fair die is 5/6.
So, the expected gain in each game is:
Take LCM
The number of games is 100.
So, the expected gain is:
Hence, the expected total gain is 83 points
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<u><em>Answer:</em></u>
79.8 (Guessing)
<u><em>Step-by-step explanation:</em></u>
for the side walls, split 19 in half, and get 9.5.
9.5 + 9.5 = 19
19 + 19 + 29.2 + 12.6
(2 walls) + (bottom floor) + (height/y)
79.8
Answer:
The answer is -7
Step-by-step explanation:
-5 - 3 = -8
-8 + 1 = -7
Hope I helped :)
Answer:
18.0167≤x≤21.9833
Step-by-step explanation:
Given the following
sample size n = 10
standard deviation s = 3.2
Sample mean = 20
z-score at 95% = 1.96
Confidence Interval = x ± z×s/√n
Confidence Interval = 20 ± 1.96×3.2/√10
Confidence Interval = 20 ± (1.96×3.2/3.16)
Confidence Interval = 20 ± (1.96×1.0119)
Confidence Interval = 20 ± 1.9833
CI = {20-1.9833, 20+1.9833}
CI = {18.0167, 21.9833}
Hence the required confidence interval is 18.0167≤x≤21.9833
