Answer:
135°
Step-by-step Explanation:
==>Given:
An inscribed quadrilateral ABCD with,
m<A = (3x +6)°
m<C = (x + 2)°
==>Required:
measure of angle A
==>Solution:
First, let's find the value of x.
Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.
Therefore, this means m<A + m<C = 180°
Thus, (3x+6) + (x+2} = 180
3x + 6 + x + 2 = 180
Collect like terms:
3x + x + 6 + 2 = 180
4x + 8 = 180
Subtract 8 from both sides:
4x + 8 - 8 = 180 - 8
4x = 172
Divide both sides by 4:
4x/4 = 172/4
x = 43
We can now find m<A = (3x + 6)°
m<A = 3(43) + 6
= 129 + 6
measure of angle A = 135°
Step-by-step explanation:
This seems to be calculus 1.
<u>Question a</u>
We have 
m = slope = derivative
Find the derivative / slope of 
We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.


when x = a
<em>Now that we have this information, we can answer question b</em>
<u>Question b</u>
<u>The tangent line for Point (1, 12)</u>
First find the slope by using our derivative.

Now that we have our slope, use point slope form to find our tangent line


<u>Now lets do the same for the Point (2, 13)</u>
Find the slope at the point.
Now find the tangent line using point slope form of a line.


Now graph the lines, which I have done and you can see by viewing the image I have attached.
The answer is 3 because all you have to do is plug in the answer and then you have to solve the answer and go from there.
Perimeter = 2L + 2W
Perimeter = 2(4x^2) + 2(y^2)
Perimeter = 8x^2 + 2y^2
x^2 - 7x^2 = -6x^2
-3x - -2x = -3x +2x = -x
8 - -1 = 8+1 = 9
Answer = -6x^2 -x + 9
9x^2 -4x - 3x^2 -2x
9x^2 - 3x^2 = 6x^2
-4x - -2x = -4x +2x = -2x
Answer = 6x^2 -2x