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siniylev [52]
3 years ago
6

Round 4,088,432 to the nearest million

Mathematics
2 answers:
olasank [31]3 years ago
8 0

Answer:

4,000,000

Step-by-step explanation:

Orlov [11]3 years ago
3 0
The answer is 4,000,000
You might be interested in
Quadrilateral ABCD is inscribed in a circle. What is the measure of angle A? Enter your answer in the box.
SashulF [63]

Answer:

135°

Step-by-step Explanation:

==>Given:

An inscribed quadrilateral ABCD with,

m<A = (3x +6)°

m<C = (x + 2)°

==>Required:

measure of angle A

==>Solution:

First, let's find the value of x.

Recall that the opposite angles in any inscribed quadrilateral in a circle are supplementary.

Therefore, this means m<A + m<C = 180°

Thus, (3x+6) + (x+2} = 180

3x + 6 + x + 2 = 180

Collect like terms:

3x + x + 6 + 2 = 180

4x + 8 = 180

Subtract 8 from both sides:

4x + 8 - 8 = 180 - 8

4x = 172

Divide both sides by 4:

4x/4 = 172/4

x = 43

We can now find m<A = (3x + 6)°

m<A = 3(43) + 6

= 129 + 6

measure of angle A = 135°

6 0
3 years ago
What fraction of box does each student receive?
Iteru [2.4K]
2.B that the answer
6 0
3 years ago
Read 2 more answers
Please help with the questions in the image
iren2701 [21]

Step-by-step explanation:

This seems to be calculus 1.

<u>Question a</u>

We have -2x^3 + 5x^2 + 9

m = slope = derivative

Find the derivative / slope of -2x^3 + 5x^2 + 9

We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.

\frac{d}{dx}(-2x^3 + 5x^2 + 9)

-6x^2 + 10x

m = -6x^2 + 10x when x = a

<em>Now that we have this information, we can answer question b</em>

<u>Question b</u>

<u>The tangent line for Point (1, 12)</u>

First find the slope by using our derivative.

m = -6x^2 + 10x

m = -6(1)^2 + 10(1)

m = -6 + 10x

m = 4

Now that we have our slope, use point slope form to find our tangent line

y - 12 = 4(x - 1)

y(x) = 4x + 8


<u>Now lets do the same for the Point (2, 13)</u>

Find the slope at the point.

m = -6x^2 + 10x

m = -6(2)^2 + 10(2)

m = -24 + 10

m = -4

Now find the tangent line using point slope form of a line.

y(x) - 13 = -4(x - 2)

y(x) = -4x + 21


Now graph the lines, which I have done and you can see by viewing the image I have attached.


6 0
3 years ago
What is (a + b)cubed when a = 7 and b = -4?<br><br> Plz help!
butalik [34]
The answer is 3 because all you have to do is plug in the answer and then you have to solve the answer and go from there.
7 0
2 years ago
I need help on this anyone
DanielleElmas [232]

Perimeter = 2L + 2W

Perimeter = 2(4x^2) + 2(y^2)

Perimeter = 8x^2 + 2y^2

x^2 - 7x^2 = -6x^2

-3x - -2x = -3x +2x = -x

8 - -1 = 8+1 = 9

Answer = -6x^2 -x + 9

9x^2 -4x - 3x^2 -2x

9x^2 - 3x^2 = 6x^2

-4x - -2x = -4x +2x = -2x

Answer = 6x^2 -2x

5 0
3 years ago
Read 2 more answers
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