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siniylev [52]
3 years ago
6

Round 4,088,432 to the nearest million

Mathematics
2 answers:
olasank [31]3 years ago
8 0

Answer:

4,000,000

Step-by-step explanation:

Orlov [11]3 years ago
3 0
The answer is 4,000,000
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A private school opened in 2005 with an initial enrollment of 85 students. The enrollment has increased by an average of 18 stud
mafiozo [28]
<span>1. Let t = time in years, with t = 0 representing the year 2005. Let f(t) = the number of students enrolled at the private school and g(t) = the number of students enrolled at the public school. Create the two functions to represent the situation.

f(t) = 85 + 18t </span>⇒ y = 85 + 18x<span>
g(t) = 95 + 15t </span>⇒ y = 95 + 15x

y = y
85 + 18x = 95 + 15x
18x - 15x = 95 - 85
3x = 10
x = 10/3
x = 3 1/3

y = 85 +18(10/3) = 85 + 180/3 = 85 + 60 = 145
y = 95 + 15(10/3) = 95 + 150/3 = 95 + 50 = 145

x = 10/3 or 3 1/3
y = 145
4 0
3 years ago
Please help quickly.Thanks :)
Klio2033 [76]
Multiply 2x-5y= -21 by 3 to make it 6x-15y= -63
Multiply 3x-3y= -18 by -5 to make it -15x+15y=90

This cancels the y’s out which leaves us with

6x=-63
&
-15x=90

x for 6x=-63 equals - 10.5 so x is - 10.5 and for -15x=90, x= -6

Then you plug in x into any equation you’d like to find y.

Let’s plug in - 10.5 into 6x... equation.

6(- 10.5)-15y=-63

63-15y= -63
-63 -63

-15y=0
y=0 and x= - 10.5. When you plug in this values it makes the equation true!

But the correct answer is the first one north. Sorry if I’m doing too much hahah


If I’m confusing here’s the right answer...


6x-15y= -63
-15x+15y=90


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Find the value of -5 - (- 6)-(-3)=
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Answer: -5-(-6)-(-3)= 4

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3 years ago
The price of a new car is reduced by 14% for the first month in order to increase the number of sales. If the initial price of
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5 0
3 years ago
2.Solve the following quadratic equations<br> i. 9x^2 - 1/16<br> ii. 2h^2 - 3h - 27
Juli2301 [7.4K]
i)~9x^2-\dfrac{1}{16}=0\iff9x^2=\dfrac{1}{16}\iff x^2=\dfrac{1}{9\cdot16}\iff \\\\x^2=\dfrac{1}{144}\iff x=\pm\sqrt{\dfrac{1}{144}}=\pm\dfrac{1}{12}\Longrightarrow\boxed{x=\pm\dfrac{1}{12}}


ii)~2h^2-3h-27=0\\\\\Delta=b^2-4ac\to \Delta=(-3)^2-4\cdot2\cdot(-27)\to\Delta=9+216=225\\\\&#10;\Longrightarrow h=\dfrac{-b\pm\sqrt{\Delta}}{2a}=\dfrac{-(-3)\pm\sqrt{225}}{2\cdot2}=\dfrac{3\pm15}{4}\\\\\begin{cases}h_1=\dfrac{3+15}{4}=\dfrac{18}{4}\iff \boxed{h_1=\dfrac{9}{2}}\\h_2=\dfrac{3-15}{4}=\dfrac{-12}{4}\iff\boxed{h_2=-3}\end{cases}

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3 years ago
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