2 is the coefficient. Y is 2.5
the measures of the angles are:
<h3>
How to find the measures of the angles?</h3>
Two angles are a linear pair if their measures add up to 180°.
Then we will have that:
∠EFG + ∠GFH = 180
Here we know that:
m∠EFG=3n+23
m∠GFH=2n+32
Replacing that we get:
3n + 23 + 2n + 32 = 180
5n + 55 = 180
5n = 180 - 55 = 125
n = 125/5 = 25
Then the measures of the angles are:
m∠EFG=3n+23 = 3*25 +23 = 98°
m∠GFH=2n+32 = 2*25 + 32 = 82°
If you want to learn more about angles:
brainly.com/question/17972372
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-30% answer is right because it lost 3 inches and 30 percent of 10 is 3.
Answer: -30%
Speed of the plane: 250 mph
Speed of the wind: 50 mph
Explanation:
Let p = the speed of the plane
and w = the speed of the wind
It takes the plane 3 hours to go 600 miles when against the headwind and 2 hours to go 600 miles with the headwind. So we set up a system of equations.
600
m
i
3
h
r
=
p
−
w
600
m
i
2
h
r
=
p
+
w
Solving for the left sides we get:
200mph = p - w
300mph = p + w
Now solve for one variable in either equation. I'll solve for x in the first equation:
200mph = p - w
Add w to both sides:
p = 200mph + w
Now we can substitute the x that we found in the first equation into the second equation so we can solve for w:
300mph = (200mph + w) + w
Combine like terms:
300mph = 200mph + 2w
Subtract 200mph on both sides:
100mph = 2w
Divide by 2:
50mph = w
So the speed of the wind is 50mph.
Now plug the value we just found back in to either equation to find the speed of the plane, I'll plug it into the first equation:
200mph = p - 50mph
Add 50mph on both sides:
250mph = p
So the speed of the plane in still air is 250mph.
