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Lyrx [107]
3 years ago
7

I need to solve for x this is easy I don't have the time to do it though ​

Mathematics
2 answers:
REY [17]3 years ago
7 0
B. x=9

5x+5x=90
10x=90
x=9
Elis [28]3 years ago
3 0
I think it’s x = 9 hope it helps :D
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Billy has $228. Amy has$53 more than Billy. How much money does Amy have?
Over [174]
228+53= 281

Your welcome.

7 0
3 years ago
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6z -2 =0 so wouldnt you take 6 from 2 which would make z=4
ser-zykov [4K]
You would not subtract 2 from 6 because they are not like terms that you can combine - one of them contains a variable.

You would solve this equation like so:

6z - 2 = 0       The given equation
6z = 2            Add 2 to both sides
z = 1/3           Divide both sides by 6

Answer:
z = 1/3

Hope this helps.
3 0
3 years ago
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Whicc expression represents the volume, in cubic units, of the composite figure?
Ann [662]

Where is the cubic figure? But just to let you know for future reference there are calculators for that all you have to do is put in the dimensions! ;)


4 0
3 years ago
If I = prt; p = 350, r = 6%, I = 42, then t = 2 A. True B. False
Liono4ka [1.6K]

t = 2 → A true

given I = PRT

to find T , divide both sides by PR

note that R = 6% = \frac{6}{100} = 0.06

T = \frac{I}{PR} = 42/( 350 × 0.06 ) = 2



4 0
3 years ago
A particle moves in a straight line so that its velocity at time
riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.  

s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75

Now we can use this value of t to formulate the position function s(t):

s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\

this is the position at time t.

to find the position at t=2

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\

s(2) = \dfrac{31}{4} = 7.75

the position of the particle at time, t =2 is s(2) = 7.75

3 0
3 years ago
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