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AysviL [449]
3 years ago
8

Pleasse and thank u <33

Mathematics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

4x-2x+3y+6x+6y          distributive property

4x-2x+6y+3y+6y          commutative property of addition

8x+9y                            combine like terms

Step-by-step explanation:

I hope this helps!

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What is the slope intercept form of the equation y+18=2(x-1)
statuscvo [17]
<h2>The slope intercept form of the given equation is: y  = 2x +  ( - 20)   </h2>

Step-by-step explanation:

Given,

The equation y + 18 = 2( x - 1)

To write the given equation in the slope intercept form = ?

∴ The equation y + 18 = 2( x - 1)

⇒ y + 18 = 2x - 2

⇒ y  = 2x - 2 - 18

⇒ y  = 2x - 20

⇒ y  = 2x +  ( - 20)                  ..... (1)

We know that,

The equation of slope intercept form,

y = mx + c

Where, m is the sope and c is the y-intercept

∴ The slope intercept form of the given equation is: y  = 2x +  ( - 20)        

8 0
3 years ago
If 1/4 of the apples was given to zion and in total was 40 what fraction for the rest was oranges
Inessa05 [86]

Answer:

3/4 of the fruits were oranges.

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
In ΔXYZ, the measure of ∠Z=90°, the measure of ∠X=65°, and ZX = 4.8 feet. Find the length of YZ to the nearest tenth of a foot.
aleksandrvk [35]

Answer:

14

Step-by-step explanation:

I do stuff

3 0
3 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
Bond [772]

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }

.

.

.

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }

.

.

.

Following the pattern, we can see that for f^{n}(x),

f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} }  \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}

This applies for n ≥ 1, Expressing f(x) in summation, we have

\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}

Combining ln2 with the rest of series, we have

f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0
2 years ago
How many hundreds are equal to 6/10
Leya [2.2K]
I believe it would be 60

8 0
4 years ago
Read 2 more answers
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