Answer:
Step-by-step explanation:
Your question is not complete.
According to what do we validate with the equation.
add more info in the question because all of them can be true without any condition given or validation.
Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Do you need the steps? g=14
Choice B.
how you can determine is to look at the x coordinates. If you see two x coordinates, and they have different corresponding y values, then the set is not a function.
Answer:
32 rooms
Step-by-step explanation:
You have to divide
