Find the median data 46,22,46,49,45,39,40,42,41,39,40,36
ddd [48]
Answer:
median is 40.5
Step-by-step explanation:
22, 36, 39, 39, 40, 40, 41, 42, 45, 46, 46, 49
half way between numbers in numerical order
lands between 40 and 41
40.5
Answer:
7
Step-by-step explanation:
3 * 3 * 3 * 3 * 3 * 3 * 3 = 
Step-by-step explanation:
A cross-section is a washer with an inner radius of 8sin(x) - (-1) and an outer radius of 8cos(x) - -(1), so its area would be:
A(x) = π[(8cos(x) + 1)^2 − (8sin(x) + 1)^2]
= π[64cos^2(x) + 16cos(x) + 1 - 64sin^2(x) − 16sin(x) − 1]
= π[64cos(2x) + 16cos(x) - 16sin(x)]
=> V(x) = ∫[0,π/4] π[64cos(2x) + 16cos(x) - 16sin(x)] dx
= π[32sin(2x) + 16sin(x) + 16cos(x)] |[0,π/4]
= π[32sin(π/2) + 16√2/2 + 16√2/2 - 16]
= π(32 - 16 + 16√2) = π(16 + 16√2)
The volume of the region is π(16 + 16√2).
