The equation that is equivalent to the given equation is 4x = 68. No answer is correct
<h3>Equations and expressions</h3>
Equations are two expressions equated to each other. Given the equation below;
- 4(x - 5) + 8x = 91 - 3
Expand
-4x + 20. + 8x = 88
Collect the like terms
4x + 20 = 88
4x = 88 - 20
4x = 68
Hence the equation that is equivalent to the given equation is 4x = 68
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Answer:
Step-by-step explanation:
A car uses 15 gallons of gas in its tank. This means the capacity of the tank is 15 gallons.
The car travels 35 miles per gallon of gas.
If the car travels 35 miles per gallon of gas, then
It uses 1/35 of a gallon of gas to go 1 mile. Let x be the amount of gas in gallons that the car would use to travel 100 miles. The amount of gas that the car will use to travel 100 miles will be
If 1 mile requires 1/35 gallons
100 miles will require x gallons
x = 1/35 × 100 = 2.86 gallons of gas
I'm guessing the question is meant to be "<span>If the radius of a circle with a area of 5.3 mm squared is multiplied by 5, what will the new area be?", so i'll answer that.
Area of a circle =</span>πr^2
5.3=πr^2, 5.3=π(5r)^2
132.5=25πr^2
Answer:
195 students
Step-by-step explanation:
585/9=65
65*3=195
1. We use the recursive formula to make the table of values:
f(1) = 35
f(2) = f(1) + f(2-1) = f(1) + f(1) = 35 + 35 = 70
f(3) = f(1) + f(3-1) = f(1) + f(2) = 35 + 70 = 105
f(4) = f(1) + f(4-1) = f(1) + f(3) = 35 + 105 = 140
f(5) = f(1) + f(5-1) = f(1) + f(4) = 35 + 140 = 175
2. We observe that the pattern is that for each increase of n by 1, the value of f(n) increases by 35. The explicit equation would be that f(n) = 35n. This fits with the description that Bill saves up $35 each week, thus meaning that he adds $35 to the previous week's value.
3. Therefore, the value of f(40) = 35*40 = 1400. This is easier than having to calculate each value from f(1) up to f(39) individually. The answer of 1400 means that Bill will have saved up $1400 after 40 weeks.
4. For the sequence of 5, 6, 8, 11, 15, 20, 26, 33, 41...
The first-order differences between each pair of terms is: 1, 2, 3, 4, 5, 6, 7, 8...since these differences form a linear equation, this sequence can be expressed as a quadratic equation. Since quadratics are functions (they do not have repeating values of the x-coordinate), therefore, this sequence can also be considered a function.