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Lyrx [107]
3 years ago
11

What is the x-intercept of the line described by the equation?

Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

(0,-6)

Step-by-step explanation:

recall that the y-intercept is simply the point where the line crosses the y-axis at x = 0.

to find the y intercept, we simply substitute x=0 into the equation and solve for y

12x - 10y = 60, when x = 0,

12(0) - 10y = 60

-10y = 60

y = 60 / (-10)

y = -6

hence the coordinate of the y - intercept is (0,-6)

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Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2

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<em>f'</em> (2) = <em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 12<em>a</em>₃ = -1

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34kurt

Given:

\begin{gathered} a=2i+3 \\ b=i-1 \\ c=-3i+2 \end{gathered}

You know that:

a-b-c=(2i+3)-(i-1)-(-3i+2)

In order to solve the operation, you can follow these steps:

1. Distribute the negative signs. Remember the Sign Rules for Multiplication:

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Answer:

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