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2 years ago

Simplify. Rewrite the expression in the form 9n. (9-3)(912)=

Mathematics

1 answer:

Yakvenalex [24]2 years ago

7 0

Answer:

Step-by-step explanation:

(9-3)*912 = 6 * 912

= 5472

= 9* 608

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write the formula for absolute value function if its graph has the vertex at point (0,6) and passes through the point (-1,-2)

Readme [11.4K]

Answer:

First you need to find the slope of the line:

m=6-(-2) / (-1)-0 =-8

equation of line is:

y=mx+b

y=-8x+6

for absolute value function:

if x<0

y=-8x+6

if x>0

y=+8x-6

Step-by-step explanation:

8 0

2 years ago

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value S₁ = 1.

• Assume the closed form is correct for all n up to n = k. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for n = k + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

3 years ago

Which of the following DOES NOT have any rectangular faces? A. pentagonal prism B. hexagonal pyramid C. rectangular prism D. squ

docker41 [41]

A pentagonal prism, a rectangular prism, and a square pyramid all have rectangular faces but a hexagonal pyramid does not.

A hexagonal pyramid only consists of a hexagon and triangles. Therefore, the answer is B. Hexagonal Pyramid.

6 0

3 years ago

Read 2 more answers

Is the given function continuous at x=1?

rusak2 [61]

Answer:

The answer is "Option C".

Step-by-step explanation:

Given:

$\to f(x)=2x^2-3x+1\\\\when \ x=1\\\\\to f(1)= 2(1)^2-3(1)+1\\\\\to f(1)= 2(1)-3+1\\\\\to f(1)= 2-3+1\\\\\to f(1)=-1+1\\\\\to f(1)=0$

That's why choice C is correct.

3 0

3 years ago

PLS HELP ASAP I REALLY NEED HELP!!!!

maks197457 [2]

Answer:

11 1/5

Step-by-step explanation:

3 1/2 + 2 57/60 + 4 3/4 =

3 30/60 + 2 57/60 + 4 45/60 =

9 132/60 = 1

1 12/60 =

11 1/5

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

7 0

2 years ago

Read 2 more answers