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marshall27 [118]
3 years ago
8

Find the solution(s) to 22 +57-3 = 0. Check all that apply.

Mathematics
1 answer:
irakobra [83]3 years ago
8 0

Answer:

x = -3 and x = 1/2

Step-by-step explanation:

To find the solutions to

2x² + 5x - 3 = 0

we can use the quadratic formula, as follows:

x = \frac{-b \pm \sqrt{b^2- 4(a)(c)}}{2(a)}

x = \frac{-5 \pm \sqrt{5^2- 4(2)(-3)}}{2(2)}

x = \frac{-5 \pm 7}{4}

x_1 = \frac{-5 + 7}{4}

x_1 = 0.5

x_2 = \frac{-5 - 7}{4}

x_2 = -3

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Step-by-step explanation:

Millimeters are extremely tiny and would only cover about 1/4 of your laptops length.

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If there are 205 students in the school, which is the best estimate of the number of students that are in the 5th grade?
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Step-by-step explanation:

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Find the mean of the following numbers; 7 21 2 17 3 14 7 4 9 7 9
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Answer:

9

Step-by-step explanation:

2,3,4,7,7,7,9,9,14,17,21

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3 0
3 years ago
Read 2 more answers
Solve using the quadratic formula 3x^2+11x+5=0
storchak [24]

Answer:

3x^2 + 11x + 5 = 0 : x = \frac{-11 + \sqrt{61} }{6} , x = \frac{-11 - \sqrt{61} }{6}

Decimal:

(x = -0.53162..., x = -3.13504...)

Step-by-step explanation:

3x^2+11x+5=0

Solve with the quadratic formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are:

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For a=3,\:b=11,\:c=5:\quad x_{1,\:2}=\frac{-11\pm \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

x=\frac{-11 + \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 + \sqrt{61} }{6}

x=\frac{-11 - \sqrt{11^2-4\cdot \:3\cdot \:5}}{2\cdot \:3} : \frac{-11 - \sqrt{61} }{6}

The solutions to the quadratic equation are:

x=\frac{-11+\sqrt{61}}{6},\:x=\frac{-11-\sqrt{61}}{6}

Hope I helped. If so, may I get brainliest and a thanks?

Thank you, have a good day! =)

8 0
3 years ago
Find two square numbers that have a sum of 130
3241004551 [841]
7 squared = 49 and 9 squared= 81 add up 49 and 81 and you get 130
8 0
3 years ago
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