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Bingel [31]
3 years ago
8

I have so many points help me

Mathematics
1 answer:
mario62 [17]3 years ago
7 0
0.33 and it keeps on repeating you’re welcome
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A line segment BK is an angle bisector of ΔABC. A line KM intersects side BC such, that BM = MK. Prove: KM ∥ AB.
weqwewe [10]

Answer:

∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK  and lies between AB and KM and BK is the transversal line)

m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)

Step-by-step explanation:

Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK

TO prove: KM ║AB

Now, As given in figure 1,

In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)

Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)

Now ∵ ∠MBK = ∠BKM

and  ∠ABK = ∠KBM

∴ ∠BKM= ∠ABK

Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)

Hence proved.  

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Graphically, a point is a solution to a system of two inequalities if and only if the point lies in the shaded region of the top
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Answer:

  lies in the shaded regions of both the top and bottom inequalities

Step-by-step explanation:

For a point to be a solution of two inequalities, it must lie in both solution sets. It ...

  lies in the shaded regions of both the top and bottom inequalities

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Answer:

I think it should be:

<h2> \frac{a^{10} }{4c^{4} }</h2>

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Pine Bluff Middle School is having its annual Spring Fling dance, which will cost $400. The student treasurer reported that the
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