Solve pls brainliest
1 answer:
You might be interested in
The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
#SPJ1
9514 1404 393
Answer:
20
Step-by-step explanation:
As with any evaluation problem, take it step by step according to the order of operations.
The first thing you need to do here is compute a#b.
The given definition can be simplified a bit for evaluation purposes:
a#b = a²b -ab² = ab(a -b)
Then for a=3 and b=-2, you have ...
(3)#(-2) = (3)(-2)(3 -(-2)) = -6(5) = -30
Now, you are in a position to evaluate the expression you're asked for.
