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Vesnalui [34]
4 years ago
7

Calculate the standard deviation of the data set below ( 7, 9, 10, 11, 13)

Mathematics
1 answer:
JulijaS [17]4 years ago
7 0
The standard deviation is 2.2
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How do yo find slope
Yuliya22 [10]
X2 minus x1/y2 minus y1 is how u find slope
6 0
3 years ago
A collar of Styrofoam is made to insulate a pipe. Find it's volume. That large R is to the outer rim. The smaller r us to the ed
anastassius [24]

Answer:

the volume of the pipe is 649.98 cubic inches.

Step-by-step explanation:

We have been given that a collar of Styrofoam is made to insulate a pipe. We are asked to find the volume of the given pipe.

We will use volume of hollow cylinder formula to solve our given problem.

\text{Volume of hollow cylinder}=\pi R^2h-\pi r^2h

where,

R = Radius of external cylinder,

r = Radius of internal cylinder.

h = Height of cylinder.

substituting our given values in above formula, we will get:

\text{Volume of hollow cylinder}=\pi (5\text{ in})^2(\text{23 in})-\pi (4\text{ in})^2(\text{23 in})\text{Volume of hollow cylinder}=\text{23 in}\cdot 3.14 ((5\text{ in})^2-(4\text{ in})^2)\text{Volume of hollow cylinder}=\text{23 in}\cdot 3.14 (25\text{ in}^2-16\text{ in}^2)\text{Volume of hollow cylinder}=\text{23 in}\cdot 3.14 (9\text{ in}^2)\text{Volume of hollow cylinder}=649.98\text{ in}^3

Therefore, the volume of the pipe is 649.98 cubic inches.

8 0
3 years ago
Does anyone know the answer to this?
FrozenT [24]

Answer:

B

Step-by-step explanation:

X is the domain.

The function comes from -∞ and goes to ∞

So B is the answer.

7 0
3 years ago
Find the final amount. ​$4000 invested at 11​% APR compounded quarterly for 5 years The final amount is ​$ nothing. ​(Do not rou
Angelina_Jolie [31]
<h3>The final amount is $ 6881.71</h3>

<em><u>Solution:</u></em>

<em><u>The formula for compound interest, including principal sum, is:</u></em>

A = p(1 + \frac{r}{n})^{nt}

Where,

A = the future value of the investment

P = the principal investment amount\

r = the annual interest rate in decimal

n = the number of times that interest is compounded per unit t

t = the time the money is invested

From given,

p = 4000

t = 5

r = 11 \% = \frac{11}{100} = 0.11

n = 4 ( compounded quarterly )

<em><u>Substituting the values in formula,</u></em>

A = 4000(1 + \frac{0.11}{4})^{4 \times 5}\\\\ A = 4000( 1.0275)^{20}\\\\A = 4000 \times 1.720428\\\\A = 6881.7137 \approx 6881.71

Thus the final amount is $ 6881.71

5 0
3 years ago
Please help.... <br> don’t understand
BlackZzzverrR [31]

5.\\a_0=24\\a_1=a_0+7\to a_1=24+7=31\\a_2=a_1+7\to a_2=31+7=38\\a_3=a_2+7\to a_3=38+7=45\\a_4=a_3+7\to a_4=45+7=52\\\vdots\\a_n=a_{n-1}+7\\\\Answer:\ \left\{\begin{array}{ccc}a_0=24\\a_{n}=a_{n-1}+7\end{array}\right

6..\\a_0=-5\\a_1=a_0\cdot(-6)\to a_1=-5(-6)+30\\a_2=a_1\cdot(-6)\to a_2=30(-6)=-180\\a_3=a_2\cdot(-6)\to a_3=-180(-6)=1080\\a_4=a_3\cdot(-6)\to a_4=1040(-6)=-6480\\\vdots\\a_n=(-6)a_{n-1}\\\\Answer:\ \left\{\begin{array}{ccc}a_0=-5\\a_n=-6a_{n-1}\end{array}\right

3 0
4 years ago
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