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dlinn [17]
3 years ago
10

The measures of 13 angles of a 14-gon add up to 2014. Find the fourteenth angle measure

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
8 0

Answer:

154.92

Step-by-step explanation:

2014/13=154.92

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What is an equation of the line that passes through the point (−6,−1) and is perpendicular to the line 6x−y=7?
user100 [1]

Answer:

y=-1/6x-2

Step-by-step explanation:

Lets find the slope of the given line

6x-7=y,m=6

The slope of the perpendicular line would be=-1/6

Using the point-slope form y-y1=m(x-x1)

y--1=-1/6(x--6)

y+1=-1/6(x+6)

6y+6=-x-6

6y=-x-6-6

6y=-x-12

y=-1/6x-2

6 0
3 years ago
X/1.5 = 4*<br> Help me plz
Anna11 [10]

Answer:

x = 6

Step-by-step explanation:

\frac{x}{1.5} =4\\\\

We can multiply both sides by 1.5 to isolate x

x=4*1.5\\x=6

4 0
2 years ago
Read 2 more answers
Since BC is parallel to DE, triangles ABC and ADE are similar. What are the lengths of the unknown sides?
Yuri [45]

Answer:

Option D. AC= 10 cm and CE= 5 cm

Step-by-step explanation:

From the given figure two triangles ΔABC and ΔADE are similar and two lines BC║DE.

From these similar triangles we know

\frac{AB}{AD}=\frac{BC}{DE}=\frac{AC}{AE}

\frac{8}{12}=\frac{BC}{9}=\frac{AC}{AE}

Therefore \frac{AC}{AE}=\frac{8}{12}=\frac{2}{3}

Or AC=\frac{2}{3}AE

Now from pythagoras theorem

AE = √(AD²+ED²) = √(12²+9²) = √(144+81) =√225 = 15 cm

Since we know side AC = \frac{2}{3}AE

                                        = \frac{2}{3}\times 15

                                        = 10 cm

Therefore AC = 10 cm and AE = 15cm and CE = (15-10) = 5 cm


8 0
3 years ago
△BCD≅△GEF . If BC=10 , CD=3x+8 and EF=4x+6 , then what is the measure of CD ?
BabaBlast [244]

Answer:

blue ray and dvds

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Need help finding the answer.
Bingel [31]

Answer:

angle 2= 52.7° (same as angle 4)

angle 1 and angle 3 = 127.3°

8 0
2 years ago
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