PLEASE HELP I NEED TO DO THIS RIGHT
2 answers:
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Answer:
For Company A to have a better deal, the truck must be driven more than 250 miles per day.
Step-by-step explanation:
Given that:
Rent per day of company A = $70
Per mile charges = $0.20
Let,
x be the number of miles.
A(x) = 0.20x + 70
Rent per day of company B = $20
Per mile charges = $0.40
B(x) = 0.40x + 20
For make Company A better deal,
A(x) > B(x)
0.20x+70 > 0.40+20
0.20x-0.40x>20-70
-0.20x>-50
Dividing both sides by -0.20
Hence,
For Company A to have a better deal, the truck must be driven more than 250 miles per day.
Answer:
f(x) = x + 3 and g(x)= - 2 ( f - g )(7t)
I'm not sure, I just tried ma best :) !
Find the intersection point between the 2 restraint equations:
Substitute back in to find y-value:
P is maximized at point (12,6)
Substitute back in to find y-value:
P is maximized at point (12,6)