Answer:
i think you should do multiplication
Step-by-step explanation: I hope that helps.
Answer:
z = -5
Step-by-step explanation:
3(0.7z + 2.8) = 7(1.5z + 7.2)
2.1z + 8.4 = 10.5z + 50.4
2.1z - 10.5z = 50.4 - 8.4
-8.4z = 42
z = 42/(-8.4)
z = -5
Answer:
The value of the quantity after 87 months will be of 599.64.
Step-by-step explanation:
A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.
This means that the quantity, after t periods of 6 years, is given by:

What is the value of the quantity after 87 months, to the nearest hundredth?
6 years = 6*12 = 72 months
So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).


The value of the quantity after 87 months will be of 599.64.
<span>2.1/1.488
</span><span>=<span>1.41129
Rounded to the nearest tenth is, </span></span><span>1.4.
I hope this helped! ;)</span>
Answer:
Step-by-step explanation:
Take a triangle ABC, in which AB=AC.
Construct AP bisector of angle A meeting BC at P.
In ∆ABP and ∆ACP
AP=AP[common]
AB=AC[given]
angle BAP=angle CAP[by construction]
Therefore, ∆ABP congurent ∆ACP[S.A.S]
This implies, angle ABP=angleACP[C.P.C.T]