All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is
Multiply both sides by <em>r</em> :
Subtract the latter sum from the first, which eliminates all but the first and last terms:
Solve for 
:
Then as gets arbitrarily large, the term 
will converge to 0, leaving us with
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Answer: 
Step-by-step explanation: 11/12 - 3/8
1. First, we will find a common denomenator. It needs to be the least common factor, or the answer will not be in its simplist form. Let's take a look at the multiples of 12 and 8.
12: 12, 24, 36, 48, 60, 72, 84, 96
8: 8, 16, 24, 32, 40, 48, 56, 64, 72
2. Next, we will choose the smallest common multiple. That would be 24.
3. Now, we will work this out.
11/12 = 22/24
3/8 = 9/24
4. Subtract.
22/24 - 9/24
= 13/24
=
I found the denomenators by multiplying.
Hope this answer helped!
The opposite angles of a quadrilateral are supplementary so you can set them equal to 180.
If there was more information given then i could find the exact values.
Hope this helps :)
Answer:
144°
Step-by-step explanation:
Hope this helps :)
Answer:
y = (x + 7)/2
here's your solution
=>. it is given. x = 2y - 7
=> we have to make y as subject
=> now, we can writ this equation in this way
=> 2y - 7 = x
=> now put all constant to right side
=> 2y = x +7
=>. y = x+ 7 /2
hope it helps
