What is the area of the circle?

Lindsey sold stationery to her family and her mother's friends shw deposited the $125 shw earned in a savings account. The accou

Leona [35]

Your Answer will be: $134.71

8 0

2 years ago

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What is the distance between (−5,−4) and (-6,4)?

Helga [31]

The distance formula is: d = sqrt( (x2 - x1)2 + (y2 - y1)2 )

For this problem, let (-5, -4) be the "first" point, so x1 = -5 and y2 = -4

and let (-6, 4) be the "second" point, so x2 = -6 and y2 = 4.

Then: d = sqrt( (-6 - -5)2 + (4 - -4)2 ) = sqrt( (-1)2 + (8)2 ) = sqrt( 1 + 64 ) = sqrt( 65)

The distance formula is just the Pythagorean Theorem applied to an x-y graph.

You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.

6 0

2 years ago

6. What will you get when you combine -14, -9 and 3 A. 12 B. 58 C.-12 D. -58

vlada-n [284]

Answer:

the answer is A I think it will help u

4 0

2 years ago

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Miko and Raj get the same salary. Every month Miko saves

navik [9.2K]

Answer:

Step-by-step explanation:

The salaries are the same. Only the fraction of how much is saved is quite different.

Equation

x ( 9/11 - 7/9) = 1584

Explanation: The salary amount is x. The fractional amounts saved are also given. You have to take the difference because one of the people saves more than the other.

The amount that is more is 1584.

Solution

9/11 = 0.8182

7/9 = 0.7778

9/11 - 7/9 = 0.8182 - 0.7778 = 0.0404

Put that into the equation.

x(0.0404) = 1584 Divide by 0.0404)

x(0.0404) = 1584/0.0404

answer:x = 39204

8 0

2 years ago

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

irga5000 [103]

Answer:

The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

Step-by-step explanation:

Let $C = (h,k)$ the coordinates of the center of the circle, which must be transformed into $C'=(h', k')$ by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

$(x-h)^{2}+(y-k)^{2} = r^{2}$

Where $r$ is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) Center of the circle is translated 4 units to the right (+x direction):

$C''(x,y) = C(x, y) + U(x,y)$ (Eq. 1)

Where $U(x,y)$ is the translation vector, dimensionless.

If we know that $C(x, y) = (h,k)$ and $U(x,y) = (4, 0)$ , then:

$C''(x,y) = (h,k)+(4,0)$

$C''(x,y) =(h+4,k)$

2) Reflection over the x-axis:

$C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)]$ (Eq. 2)

Where $O(x,y)$ is the reflection point, dimensionless.

If we know that $O(x,y) = (h+4,0)$ and $C''(x,y) =(h+4,k)$ , the new point is:

$C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]$

$C'(x,y) = (h+4, 0)-(0,k)$

$C'(x,y) = (h+4, -k)$

And thus, $h' = h+4$ and $k' = -k$ . The statement is now presented as:

$\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}$

In other words, this mathematical statement can be translated as:

There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r.

4 0

3 years ago